FileUpload with Django

Question

I\'m using the ajax-upload code to do a simple AJAX file upload. The issue I\'m coming across is the file isn\'t showing up on the backend after submitting.

The frontend

Answer 1

Andrew Valums has now got a django app at git hub

Answer 2

For me, using code from Alex Kuhl, request.GET['qqfile'] had the filename and request.read() (in Django 1.3) returned the data.

request.FILES was only used in a scenario that hasn't yet happened for me. I'm using ajax-upload to talk directly to Photologue, and my code looks something like this:

def save_upload( uploaded, filename, raw_data ):
    """
    raw_data: if True, upfile is a HttpRequest object with raw post data
    as the file, rather than a Django UploadedFile from request.FILES
    """
    try:
        filename = os.path.normpath(os.path.join(IMAGE_UPLOAD_PATH, filename))
        with BufferedWriter( FileIO( filename, "wb" ) ) as dest:
            # if the "advanced" upload, read directly from the HTTP request
            # with the Django 1.3 functionality
            if raw_data:
                (dirName, fileName) = os.path.split(filename)
                (fileBaseName, fileExtension)=os.path.splitext(fileName)
                #
                # right here, if fileBaseName is less than n characters, might want to slap on a date just for fun
                #
                try:
                    i_can_has_p = Photo.objects.get(title=fileBaseName)
                    title = fileBaseName + "_" + str(datetime.datetime.now().strftime("%Y%m%dT%H%M%S"))
                except Photo.DoesNotExist:
                    title = fileBaseName
                title_slug = slugify(title)
                p = Photo(title=title, title_slug=title_slug)
                p.image.save(filename,ContentFile(uploaded.read()))
            # if not raw, it was a form upload so read in the normal Django chunks fashion
            else:
                # TODO: figure out when this gets called, make it work to save into a Photo like above
                for c in uploaded.chunks( ):
                    dest.write( c )
    except IOError:
        # could not open the file most likely
        return False
    return True

def ajax_upload( request ):
  if request.method == "POST":
      # AJAX Upload will pass the filename in the querystring if it is the "advanced" ajax upload
      if request.is_ajax( ):
          # the file is stored raw in the request
          upload = request
          is_raw = True
          try:
              filename = request.GET[ 'qqfile' ]
          except KeyError:
              return HttpResponseBadRequest( "AJAX request not valid" )
      # not an ajax upload, so it was the "basic" iframe version with submission via form
      else:
          is_raw = False
          if len( request.FILES ) == 1:
              # FILES is a dictionary in Django but Ajax Upload gives the uploaded file an
              # ID based on a random number, so it cannot be guessed here in the code.
              # Rather than editing Ajax Upload to pass the ID in the querystring, note that
              # each upload is a separate request so FILES should only have one entry.
              # Thus, we can just grab the first (and only) value in the dict.
              upload = request.FILES.values( )[ 0 ]
          else:
              raise Http404( "Bad Upload" )
          filename = upload.name

  # save the file
  success = save_upload( upload, filename, is_raw )

  # let Ajax Upload know whether we saved it or not
  ret_json = { 'success': success, }
  return HttpResponse( json.dumps( ret_json ) )

In my case, ajax_upload is the function called by ajax's action: parameter