How do I write a batch script that copies one directory to another, replaces old files?

Question

I\'d like a batch script in Windows with which I can copy one directory to another. If this directory already exists, and then for each file that already exists in both with the

Answer 1

It seems that the latest function for this in windows 7 is robocopy.

Usage example:

robocopy <source> <destination> /e /xf <file to exclude> <another file>

/e copies subdirectories including empty ones, /xf excludes certain files from being copied.

More options here: http://technet.microsoft.com/en-us/library/cc733145(v=ws.10).aspx

Answer 2

Try this:

xcopy %1 %2 /y /e

The %1 and %2 are the source and destination arguments you pass to the batch file. i.e. C:\MyBatchFile.bat C:\CopyMe D:\ToHere

Answer 3

In your batch file do this

set source=C:\Users\Habib\test
set destination=C:\Users\Habib\testdest\
xcopy %source% %destination% /y

If you want to copy the sub directories including empty directories then do:

xcopy %source% %destination% /E /y

If you only want to copy sub directories and not empty directories then use /s like:

xcopy %source% %destination% /s /y

Answer 4

Have you considered using the "xcopy" command?

The xcopy command will do all that for you.

Answer 5

Just use xcopy /y source destination