serializing objects to json with play.api.libs.json

Question

I\'m trying to serialize some relatively simple models into json. For example, I\'d like to get the json representation of:

case class User(val id: Long, val fir         


        

Answer 1

Yes, writing your own Format instance is the recommended approach. Given the following class, for example:

case class User(
  id: Long, 
  firstName: String,
  lastName: String,
  email: Option[String]
) {
  def this() = this(0, "","", Some(""))
}

The instance might look like this:

import play.api.libs.json._

implicit object UserFormat extends Format[User] {
  def reads(json: JsValue) = User(
    (json \ "id").as[Long],
    (json \ "firstName").as[String],
    (json \ "lastName").as[String],
    (json \ "email").as[Option[String]]
  )

  def writes(user: User) = JsObject(Seq(
    "id" -> JsNumber(user.id),
    "firstName" -> JsString(user.firstName),
    "lastName" -> JsString(user.lastName),
    "email" -> Json.toJson(user.email)
  ))
}

And you'd use it like this:

scala> User(1L, "Some", "Person", Some("s.p@example.com"))
res0: User = User(1,Some,Person,Some(s.p@example.com))

scala> Json.toJson(res0)
res1: play.api.libs.json.JsValue = {"id":1,"firstName":"Some","lastName":"Person","email":"s.p@example.com"}

scala> res1.as[User]
res2: User = User(1,Some,Person,Some(s.p@example.com))

See the documentation for more information.

Answer 2

Thanks to the fact User is a case class you could also do something like this:

implicit val userImplicitWrites = Json.writes[User]
val jsUserValue = Json.toJson(userObject)

without writing your own Format[User]. You could do the same with reads:

implicit val userImplicitReads = Json.reads[User]

I haven't found it in the docs, here is the link to the api: http://www.playframework.com/documentation/2.2.x/api/scala/index.html#play.api.libs.json.Json$