I\'m searching text \"Cheese!\" on google homepage and unsure how can I can click on the searched links after pressing the search button. For example I wanted to click the third
public class GoogleSearch {
public static void main(String[] args) {
WebDriver driver=new FirefoxDriver();
driver.get("http://www.google.com");
driver.findElement(By.xpath("//input[@type='text']")).sendKeys("Cheese");
driver.findElement(By.xpath("//button[@name='btnG']")).click();
driver.manage().timeouts().implicitlyWait(30,TimeUnit.SECONDS);
driver.findElement(By.xpath("(//h3[@class='r']/a)[3]")).click();
driver.manage().timeouts().implicitlyWait(30,TimeUnit.SECONDS);
}
}
@Test
public void google_Search()
{
WebDriver driver;
driver = new FirefoxDriver();
driver.get("http://www.google.com");
driver.manage().window().maximize();
WebElement element = driver.findElement(By.name("q"));
element.sendKeys("Cheese!\n");
element.submit();
//Wait until the google page shows the result
WebElement myDynamicElement = (new WebDriverWait(driver, 10)).until(ExpectedConditions.presenceOfElementLocated(By.id("resultStats")));
List<WebElement> findElements = driver.findElements(By.xpath("//*[@id='rso']//h3/a"));
//Get the url of third link and navigate to it
String third_link = findElements.get(2).getAttribute("href");
driver.navigate().to(third_link);
}
Google shrinks their css classes etc., so it is not easy to identify everything.
Also you have the problem that you have to "wait" until the site shows the result. I would do it like this:
public static void main(String[] args) {
WebDriver driver = new FirefoxDriver();
driver.get("http://www.google.com");
WebElement element = driver.findElement(By.name("q"));
element.sendKeys("Cheese!\n"); // send also a "\n"
element.submit();
// wait until the google page shows the result
WebElement myDynamicElement = (new WebDriverWait(driver, 10))
.until(ExpectedConditions.presenceOfElementLocated(By.id("resultStats")));
List<WebElement> findElements = driver.findElements(By.xpath("//*[@id='rso']//h3/a"));
// this are all the links you like to visit
for (WebElement webElement : findElements)
{
System.out.println(webElement.getAttribute("href"));
}
}
This will print you:
Based on quick inspection of google web, this would be CSS path to links in page list
ol[id="rso"] h3[class="r"] a
So you should do something like
String path = "ol[id='rso'] h3[class='r'] a";
driver.findElements(By.cssSelector(path)).get(2).click();
However you could also use xpath
which is not really recommended as a best practice and also JQuery locators but I am not sure if you can use them aynywhere else except inArquillian Graphene
There would be multiple ways to find an element (in your case the third Google Search result).
One of the ways would be using Xpath
#For the 3rd Link
driver.findElement(By.xpath(".//*[@id='rso']/li[3]/div/h3/a")).click();
#For the 1st Link
driver.findElement(By.xpath(".//*[@id='rso']/li[2]/div/h3/a")).click();
#For the 2nd Link
driver.findElement(By.xpath(".//*[@id='rso']/li[1]/div/h3/a")).click();
The other options are
By.ByClassName
By.ByCssSelector
By.ById
By.ByLinkText
By.ByName
By.ByPartialLinkText
By.ByTagName
To better understand each one of them, you should try learning Selenium on something simpler than the Google Search Result page.
Example - http://www.google.com/intl/gu/contact/
To Interact with the Text input field with the placeholder "How can we help? Ask here." You could do it this way -
# By.ByClassName
driver.findElement(By.ClassName("searchbox")).sendKeys("Hey!");
# By.ByCssSelector
driver.findElement(By.CssSelector(".searchbox")).sendKeys("Hey!");
# By.ById
driver.findElement(By.Id("query")).sendKeys("Hey!");
# By.ByName
driver.findElement(By.Name("query")).sendKeys("Hey!");
# By.ByXpath
driver.findElement(By.xpath(".//*[@id='query']")).sendKeys("Hey!");
Simple Xpath for locating Google search box is: Xpath=//span[text()='Google Search']