Pagination for search results laravel 5.3

Question

Pagination search results

I have just started with Laravel and I am trying to make a search function with proper pagination. The function works for page one but on pag

Answer 1

If you want to apply filters to the next page you should add them to your paginator like this:

$product = Product::where('naam', 'LIKE', '%' . $q . '%')
        ->orWhere('beschrijving', 'LIKE', '%' . $q . '%')
        ->paginate(6);
$product->appends(['search' => $q]);

And change your route from post to get:

Route::get('search', 'IndexController@search');

Answer 2

in my case, i've laravel 5.7 installed.

$perPage = $request->per_page ?? 10;

$data['items'] = User::where('name', 'like', '%'. $request->search . '%')
                         ->paginate($perPage)
                         ->appends(['search' => $request->search, 'per_page' => $request->per_page]);

    return view('users.index', $data);

and my view files codes are

for per_page select dropdown and search area

<form role="form" class="form-inline" method="get" action='{{ url('/user') }}'>
 <div class="row">
  <div class="col-sm-6">
   <div class="dataTables_length">
     <label>Show
     <select name="per_page"
       onchange="this.form.submit()"
       class="form-control input-sm">
      <option value=""></option>
      <option value="10" {{ $items->perPage() == 10 ? 'selected' : '' }}>10
      </option>
      <option value="25" {{ $items->perPage() == 25 ? 'selected' : '' }}>25
      </option>
      <option value="50" {{ $items->perPage() == 50 ? 'selected' : '' }}>50
      </option>
     </select>
     entries
     </label>
    </div>
   </div>

<div class="col-sm-6">
 <div class="dataTables_filter pull-right">
  <div class="form-group">
   <label>Search: &nbsp;
   <input type="search" name="search" class="form-control input-sm"
   placeholder="Name" value="{{ request()->search }}">
   </label>
  </div>
 </div>
</div>

and my pagination generator code

{{ $items->appends(['search' => request()->search, 'per_page' => request()->per_page])->links() }}

Answer 3

For pagination, you should create a simple form:

<form action="{{URL::to('/search')}}" method="post">
    <input type="hidden" name="query"/>
    <select name="pages">
    @for($p = 1; $p < $products->lastPage(); $p++ )
        <option value="{{ $p }}">{{ $p }}</option>
    @endfor
    </select>
</form>

Pagination methods are here:

$results->count()
$results->currentPage()
$results->firstItem()
$results->hasMorePages()
$results->lastItem()
$results->lastPage() (Not available when using simplePaginate)
$results->nextPageUrl()
$results->perPage()
$results->previousPageUrl()
$results->total() (Not available when using simplePaginate)
$results->url($page)

Answer 4

I assume you want to change pages with urls like this search/1, search/2? First of all your route should be probably Route::post('search/{page?}').

I'm not sure if only this change will work, but if it does not, you have to resolve page like this

public function search(\Illuminate\Http\Request $request, $page = 1)
{
    $q = $request->get('search');

    \Illuminate\Pagination\Paginator::currentPageResolver(function () use ($page) {
        return $page;
    });

    # going to next page is not working yet
    $product = Product::where('naam', 'LIKE', '%' . $q . '%')
        ->orWhere('beschrijving', 'LIKE', '%' . $q . '%')
        ->paginate(6);

    return view('pages.index', compact('product'));
}