Pagination for search results laravel 5.3

Question

Pagination search results

I have just started with Laravel and I am trying to make a search function with proper pagination. The function works for page one but on pag

Answer 1

a quick way in view (Lavarel 5.7)

$product->appends(Request::all())->links();

Answer 2

Route::get('product', function () {
    $product= App\product::paginate(15);

    $product->setPath('custom/url');

});

View:

{{ $product->appends(['search' => Request::get('page')])->links() }}

Answer 3

In your view file where you display pagination...

{{ $results->appends(Request::except('page'))->links() }}

appends keeps the query string value except "page".

Answer 4

If you are using search form with GET method then use something like these to preserve pagination withing search results.

 public function filter(Request $request)
    {        
        $filter = $request->only('name_operator','name_value','email_operator','email_value', 'phone_operator','phone_value',   'gender_value', 'age_operator','age_value');
        $contacts = $this->repo->getFilteredList(array_filter($filter));
        $contacts->appends($filter)->links(); //Continue pagination with results
        return view('dashboard::index', compact('contacts'))->withInput($request->all());
    }

Answer 5

$searchdata =  \Request::get( 'inputTextFieldname' ); \make as global
$searchresult = Modelname::where ( 'blogpost_title', 'LIKE', '%' .$searchdata . '%' )->paginate(2);
return view( 'search', compact('searchresult') );

and in your view page

{{$searchresult->appends(Request::only('inputTextFieldname'))->links()}}

make your route to get method

Route::get('/search', ['as' => 'search', 'uses' => 'searchController@index']);

this will be done, thanks,

Answer 6

use any in route Instead post Route::any('search', 'IndexController@search');