How to appendReplacement on a Matcher group instead of the whole pattern?

Question

I am using a while(matcher.find()) to loop through all of the matches of a Pattern. For each instance or match of that pattern it finds, I want to replace ma

Answer 1

I see this already has an accepted answer, but it is not fully correct. The correct answer appears to be something like this:

.appendReplacement("$1" + process(m.group(2)) + "$3");

This also illustrates that "$" is a special character in .appendReplacement. Therefore you must take care in your "process()" function to replace all "$" with "\$". Matcher.quoteReplacement(replacementString) will do this for you (thanks @Med)

The previous accepted answer will fail if either groups 1 or 3 happen to contain a "$". You'll end up with "java.lang.IllegalArgumentException: Illegal group reference"

Answer 2

Let's say your entire pattern matches "(prefix)(infix)(suffix)", capturing the 3 parts into groups 1, 2 and 3 respectively. Now let's say you want to replace only group 2 (the infix), leaving the prefix and suffix intact the way they were.

Then what you do is you append what group(1) matched (unaltered), the new replacement for group(2), and what group(3) matched (unaltered), so something like this:

matcher.appendReplacement(
    buffer,
    matcher.group(1) + processTheGroup(matcher.group(2)) + matcher.group(3)
);

This will still match and replace the entire pattern, but since groups 1 and 3 are left untouched, effectively only the infix is replaced.

You should be able to adapt the same basic technique for your particular scenario.