sqlalchemy,creating an sqlite database if it doesn't exist

Question

I am trying out sqlalchemy and i am using this connection string to connect to my databases

engine = create_engine(\'sqlite:///C:\\\\sqlitedbs\\\\database.db\')
         


        

Answer 1

I found (using sqlite+pysqlite) that if the directory exists, it will create it, but if the directory does not exist it throws an exception:

OperationalError: (sqlite3.OperationalError) unable to open database file

My workaround is to do this, although it feels nasty:

    if connection_string.startswith('sqlite'):
        db_file = re.sub("sqlite.*:///", "", connection_string)
        os.makedirs(os.path.dirname(db_file), exist_ok=True)
    self.engine = sqlalchemy.create_engine(connection_string)

Answer 2

Yes,sqlalchemy does create a database for you.I confirmed it on windows using this code

from sqlalchemy import create_engine, ForeignKey
from sqlalchemy import Column, Date, Integer, String
from sqlalchemy.ext.declarative import declarative_base

engine = create_engine('sqlite:///C:\\sqlitedbs\\school.db', echo=True)
Base = declarative_base()


class School(Base):

    __tablename__ = "woot"

    id = Column(Integer, primary_key=True)
    name = Column(String)  


    def __init__(self, name):

        self.name = name    


Base.metadata.create_all(engine)

Answer 3

As others have posted, SQLAlchemy will do this automatically. I encountered this error, however, when I didn't use enough slashes!

I used SQLALCHEMY_DATABASE_URI="sqlite:///path/to/file.db" when I should have used four slashes: SQLALCHEMY_DATABASE_URI="sqlite:////path/to/file.db"

Answer 4

Linux stored SQLite3 database

database will be create in the same folder as the .py file:

engine = create_engine('sqlite:///school.db', echo=True)

will instantiate the school.db file in the same folder as the .py file.