Removing _id element from Pymongo results

Question

I\'m attempting to create a web service using MongoDB and Flask (using the pymongo driver). A query to the database returns documents with the \"_id\" field included, of course

Answer 1

Above answer fails if we want specific fields and still ignore _id. Use the following in such cases:

db.collection.find({'required_column_A':1,'required_col_B':1, '_id': False})

Answer 2

You are calling

del objects['_id']

on the cursor object!

The cursor object is obviously an iterable over the result set and not single document that you can manipulate.

for obj in objects:
     del obj['_id']

is likely what you want.

So your claim is completely wrong as the following code shows:

import pymongo

c = pymongo.Connection()
db = c['mydb']
db.foo.remove({})
db.foo.save({'foo' : 42})

for row in db.foo.find():
    del row['_id']
    print row



$ bin/python foo.py 

> {u'foo': 42}

Answer 3

To exclude the _id field in a find query in pymongo, you can use:

db.collection.find({}, {'_id': False})

The documentation is somewhat missleading on this as it says the _id field is always included. But you can exclude it like shown above.