The following code replaces only one single quote:
replaceAll(search, replaceWith)
replaces ALL occurrences of search
with replaceWith
.
Then, make sure you have a string by wrapping one type of qoutes by different type:
"a 'b' c".replaceAll("'", '"')
// result: "a "b" c"
"a 'b' c".replaceAll(`'`, `"`)
// result: "a "b" c"
replaceAll (MDN): replaceAll(search, replaceWith)
It's actually the same as using replace()
with a global regex(*), merely replaceAll()
is a bit more readable in my view.
(*) Meaning it'll match all occurrences.
Example 1 - search with a string
const p = 'Please replace all 2020 occurrences with 2021. 2020. 2020.'
console.log(p.replaceAll('2020', '2021'));
// Result: "Please replace all 2021 occurrences with 2021. 2021. 2021."
Example 2 - search with regex
const p = 'Please replace all 2020 occurrences with 2021. 2020. 2020.'
const regex = /2020/gi
console.log(p.replaceAll(regex, '2021'));
// Result: "Please replace all 2021 occurrences with 2021. 2021. 2021."
Important(!) if you choose regex:
when using a
regexp
you have to set the global ("g") flag; otherwise, it will throw a TypeError: "replaceAll must be called with a global RegExp".
You can also use a function as replaceWith
In this case, the function will be invoked after the match has been performed. The function's result (return value) will be used as the replacement string.