Average 2 hex colors together in javascript

Question

Alright thought I would throw this one out there for the crowd to think over.

Given a function (written in javascript) that expects two strings

Answer 1

Here is my function, hope it helps.

function averageColors( colorArray ){
    var red = 0, green = 0, blue = 0;

    for ( var i = 0; i < colorArray.length; i++ ){
        red += hexToR( "" + colorArray[ i ] + "" );
        green += hexToG( "" + colorArray[ i ] + "" );
        blue += hexToB( "" + colorArray[ i ] + "" );
    }

    //Average RGB
    red = (red/colorArray.length);
    green = (green/colorArray.length);
    blue = (blue/colorArray.length);

    console.log(red + ", " + green + ", " + blue);
    return new THREE.Color( "rgb("+ red +","+ green +","+ blue +")" );
}

//get the red of RGB from a hex value
function hexToR(h) {return parseInt((cutHex( h )).substring( 0, 2 ), 16 )}

//get the green of RGB from a hex value
function hexToG(h) {return parseInt((cutHex( h )).substring( 2, 4 ), 16 )}

//get the blue of RGB from a hex value
function hexToB(h) {return parseInt((cutHex( h )).substring( 4, 6 ), 16 )}

//cut the hex into pieces
function cutHex(h) {if(h.charAt(1) == "x"){return h.substring( 2, 8 );} else {return h.substring(1,7);}}

Answer 2

A quick/dirty/convenient/ES6 way to blend two hex colors by a specified perecentage:

// blend two hex colors together by an amount
function blendColors(colorA, colorB, amount) {
  const [rA, gA, bA] = colorA.match(/\w\w/g).map((c) => parseInt(c, 16));
  const [rB, gB, bB] = colorB.match(/\w\w/g).map((c) => parseInt(c, 16));
  const r = Math.round(rA + (rB - rA) * amount).toString(16).padStart(2, '0');
  const g = Math.round(gA + (gB - gA) * amount).toString(16).padStart(2, '0');
  const b = Math.round(bA + (bB - bA) * amount).toString(16).padStart(2, '0');
  return '#' + r + g + b;
}

console.log(blendColors('#00FF66', '#443456', 0.5));

Where amount should be 0 to 1, with 0 being exactly colorA, 1 being exactly colorB, and 0.5 being the "midpoint".