There might be a better way to do this, but I\'m trying to make an if statement in rails, based on the current action, in a controller (this will be used in a view).
For
It's not good practice IMO to have partials asking what the current controller and action names are. Think "tell, don't ask" (http://www.pragprog.com/articles/tell-dont-ask). That is, rather than having the partial ask it's caller about its state, tell the partial what you want it to do.
One way to do this is by passing variables to the partial through the locals
option:
<%= render :partial => "/common/toolbar", :locals => {:edit => true} %>
Then in the partial:
<% if defined?(edit) && edit %>
... stuff appropriate to edit mode
<% end %>
The params
hash that is available in the controller contains :controller
and :action
keys, which specify the controller and action names of the request.
Therefore you could say
if params[:action] == "foo"
# Show stuff for action 'foo'
elsif params[:action] == "bar"
# Show stuff for action 'bar'
elsif ...
# etc.
end
You can use layouts for partials too:
<%= render :partial => 'some_partial', :layout => 'wrap_with_stuff' %>
If you want to work out what layout to use dynamically I'd put that in a helper. So you'd end up with
# In your view
<%= render :partial => 'some_partial', :layout => layout_for_my_partial %>
# In your helper
def layout_for_my_partial
params[:action] == 'show' ? 'show_wrapper' : 'everything_else_wrapper'
end
This will only work in some circumstances, but might be what you're trying to do.
See more here.
http://ryandaigle.com/articles/2007/8/3/what-s-new-in-edge-rails-partials-get-layouts
You can do it this way:
class ApplicationController < ActionController::Base
layout :set_layout
def set_layout
case params[:action]
when "foo"
"foo_layout"
when "bar"
"bar_layout"
...
else
"default_layout"
end
end
...
end
hope it helps =)