Python: get list indexes using regular expression?

Question

In Python, how do you get the position of an item in a list (using list.index) using fuzzy matching?

For example, how do I get the indexes of all fruit of t

Answer 1

With regular expressions:

import re
fruit_list = ['raspberry', 'apple', 'strawberry']
berry_idx = [i for i, item in enumerate(fruit_list) if re.search('berry$', item)]

And without regular expressions:

fruit_list = ['raspberry', 'apple', 'strawberry']
berry_idx = [i for i, item in enumerate(fruit_list) if item.endswith('berry')]

Answer 2

with a function :

import re
fruit_list = ['raspberry', 'apple', 'strawberry']
def grep(yourlist, yourstring):
    ide = [i for i, item in enumerate(yourlist) if re.search(yourstring, item)]
    return ide

grep(fruit_list, "berry$")

Answer 3

Try:

fruit_list = ['raspberry', 'apple', 'strawberry']
[ i for i, word in enumerate(fruit_list) if word.endswith('berry') ]

returns:

[0, 2]

Replace endswith with a different logic according to your matching needs.