Python dictionary search values for keys using regular expression

Question

I am trying to implement to search for a value in Python dictionary for specific key values (using regular expression as a key).

Example:

I have a Python dictio

Answer 1

You can solve this with dpath.

http://github.com/akesterson/dpath-python

dpath lets you search dictionaries with a glob syntax on the keys, and to filter the values. What you want is trivial:

$ easy_install dpath
>>> dpath.util.search(MY_DICT, 'seller_account*')

... That will return you a big merged dictionary of all the keys matching that glob. If you just want the paths and values:

$ easy_install dpath
>>> for (path, value) in dpath.util.search(MY_DICT, 'seller_account*', yielded=True):
>>> ... # do something with the path and value

Answer 2

If you only need to check keys that are starting with "seller_account", you don't need regex, just use startswith()

my_dict={'account_0':123445,'seller_account':454545,'seller_account_0':454676, 'seller_account_number':3433343}

for key, value in my_dict.iteritems():   # iter on both keys and values
        if key.startswith('seller_account'):
                print key, value

or in a one_liner way :

result = [(key, value) for key, value in my_dict.iteritems() if key.startswith("seller_account")]

NB: for a python 3.X use, replace iteritems() by items() and don't forget to add () for print.

Answer 3

def search(dictionary, substr):
    result = []
    for key in dictionary:
        if substr in key:
            result.append((key, dictionary[key]))   
    return result

>>> my_dict={'account_0':123445,'seller_account':454545,'seller_account_0':454676, 'seller_account_number':3433343}
>>> search(my_dict, 'seller_account')
[('seller_account_number', 3433343), ('seller_account_0', 454676), ('seller_account', 454545)]