I had a quick question regarding the datacontractserializer. Maybe it\'s more of a stream question. I found a piece of code that writes the xml to a filestream. I basically don\
And even easier:
var serializer = new DataContractSerializer(typeof(T));
var sb = new StringBuilder();
using (var writer = XmlWriter.Create(sb))
{
serializer.WriteObject(writer, objectToSerialize);
writer.Flush();
return sb.ToString();
}
Thanks to @xr280xr for pointing out my forgotten StringWriter disposal in the first draft.
/// <summary>
/// Converts this instance to XML.
/// </summary>
/// <returns>XML representing this instance.</returns>
public string ToXml()
{
var serializer = new DataContractSerializer(this.GetType());
using (var output = new StringWriter())
using (var writer = new XmlTextWriter(output) { Formatting = Formatting.Indented })
{
serializer.WriteObject(writer, this);
return output.GetStringBuilder().ToString();
}
}
I suggest combining the methods given by Pat and marc_s:
public static string DataContractSerializeObject<T>(T objectToSerialize)
{
using (var output = new StringWriter())
using (var writer = new XmlTextWriter(output) {Formatting = Formatting.Indented})
{
new DataContractSerializer(typeof (T)).WriteObject(writer, objectToSerialize);
return output.GetStringBuilder().ToString();
}
}
A variant of @root's answer:
var serializer = new DataContractSerializer(typeof(T));
var sb = new StringBuilder();
using (var writer = XmlWriter.Create(sb))
{
serializer.WriteObject(writer, objectToSerialize);
}
return sb.ToString();
Something like this - put your output into a MemoryStream
and then read that back in:
public static string DataContractSerializeObject<T>(T objectToSerialize)
{
using(MemoryStream memStm = new MemoryStream())
{
var serializer = new DataContractSerializer(typeof(T));
serializer.WriteObject(memStm, objectToSerialize);
memStm.Seek(0, SeekOrigin.Begin);
using(var streamReader = new StreamReader(memStm))
{
string result = streamReader.ReadToEnd();
return result;
}
}
}