I want to do something like this:
>>> mystring = \"foo\"
>>> print(mid(mystring))
Help!
These work great for reading left / right "n" characters from a string, but, at least with BBC BASIC, the LEFT$()
and RIGHT$()
functions allowed you to change the left / right "n" characters too...
E.g.:
10 a$="00000"
20 RIGHT$(a$,3)="ABC"
30 PRINT a$
Would produce:
00ABC
Edit : Since writing this, I've come up with my own solution...
def left(s, amount = 1, substring = ""):
if (substring == ""):
return s[:amount]
else:
if (len(substring) > amount):
substring = substring[:amount]
return substring + s[:-amount]
def right(s, amount = 1, substring = ""):
if (substring == ""):
return s[-amount:]
else:
if (len(substring) > amount):
substring = substring[:amount]
return s[:-amount] + substring
To return n characters you'd call
substring = left(string,<n>)
Where defaults to 1 if not supplied. The same is true for right()
To change the left or right n characters of a string you'd call
newstring = left(string,<n>,substring)
This would take the first n characters of substring and overwrite the first n characters of string, returning the result in newstring. The same works for right().