Remove object from array of objects

Question

I have an array of objects:

[{\"value\":\"14\",\"label\":\"7\"},{\"value\":\"14\",\"label\":\"7\"},{\"value\":\"18\",\"label\":\"7\"}]

How I ca

Answer 1

Do you need to keep the duplicate object?

With underscoreJS

var oldarray = [{"value":"14","label":"7"},{"value":"14","label":"7"},{"value":"18","label":"7"}]
var newarray = _.reject(oldarray, function(o) { 
  return o == {"value":"14","label":"7"}; 
});

Answer 2

I would create a new array...

var original = [{"value":"14","label":"7"},{"value":"14","label":"7"},{"value":"18","label":"7"}]

var result = [];

for (var i = 0, l = original.length; i < l; i++) { // Traverse the whole array
  var current = original[i];
  if (! (current.value == 14 && current.label == 7) ) {
    // It doesn't match the criteria, so add it to result
    result.push( current );
  }
}

Edit: I've read your question once more. You only want to remove the first element? Then use slice to get only a part of the array.

var result = original.slice(1, original.length)

or splice

original.splice(0,1); // Remove one element from index 0.

Answer 3

Try:

var ar = [{"value":"14","label":"7"},{"value":"14","label":"7"},{"value":"18","label":"7"}];

for(var i=0; i < ar.length; i++) {
   if(ar[i].value == "14" && ar[i].label == "7")
   {
      ar.splice(i,1);
   }
}

demo

Answer 4

In ES6 (or using es6-shim) you can use Array.prototype.findIndex along with Array.prototype.splice:

arr.splice(arr.findIndex(matchesEl), 1);

function matchesEl(el) {
    return el.value === '14' && el.label === '7';
}

Or if a copy of the array is ok (and available since ES5), Array.prototype.filter's the way to go:

var withoutEl = arr.filter(function (el) { return !matchesEl(el); });

Answer 5

Using ES6 approach:

const objIndex = objs.findIndex(o => o.value === '14' && o.label === '7')

if(objIndex > -1) {
  objs.slice(objIndex, 1)
}

Answer 6

Here is a way to do it without 'creating a new array' or using external libraries. Note that this will only remove the first instance found, not duplicates, as stated in your question's example.

// Array to search
var arr = [{"value":"14","label":"7"},{"value":"14","label":"7"},{"value":"18","label":"7"}];

// Object to remove from arr
var remove = {"value":"14","label":"7"};

// Function to determine if two objects are equal by comparing
// their value and label properties
var isEqual = function(o1, o2) {
    return o1 === o2 || 
        (o1 != null && o2 != null && 
         o1.value === o2.value &&
         o1.label === o2.label);
};

// Iterate through array and determine if remove is in arr
var found = false;
var i;
for(i = 0; i < arr.length; ++i) {
    if(isEqual(arr[i], remove)) {
        found = true;
        break;
    }
}

if(found) {
    // Found remove in arr, remove it
    arr.splice(i, 1);
}

Demo