Bash - How to pass arguments to a script that is read via standard input

Question

I am trying execute a script from standard input and also pass arguments to it. Is there a way to do it?

Let\'s say that I have the following:

cat script         


        

Answer 1

After @ccarton's comment:

cat script.sh | bash -s - arguments

It's more portable than @Michael Hoffman's solution.

Answer 2

On Linux,

cat script.sh | bash /dev/stdin arguments

seems to work.