In a table xyz I have a row called components and a labref row which has labref number as shown here
Table xyz
labref component
NDQA201303001
You need to do -
SELECT
COUNT(*)
FROM
(
SELECT
DISTINCT component
FROM
`multiple_sample_assay_abc`
WHERE
labref = 'NDQA201303001'
) AS DerivedTableAlias
You can also avoid subquery as suggested by @hims056 here
Try this simple query without a sub-query:
SELECT COUNT(DISTINCT component) AS TotalRows
FROM xyz
WHERE labref = 'NDQA201303001';
Select labref , component ,Count(*) as Counts From xyz Group by labref , component
Why not use num_rows.
If you do it using this method, You don't have to modify the query in any way.
if ($result = $mysqli->query("SELECT DISTINCT component, COUNT( component )
FROM `xyz`
WHERE labref = 'NDQA201303001'
GROUP BY component")){
/* determine number of rows result set */
$row_cnt = $result->num_rows;
printf("Result set has %d rows.\n", $row_cnt);
/* close result set */
$result->close();
}
I found the solution. So, if you want to count quantity of groups, not quantity of elements in each group, and return duplicate value to every group record in result table, you should use OVER() clause on you'r count function.
So, for example above the solution would be
SELECT component, COUNT(*) OVER() as number_of_components FROM `xyz`
WHERE labref = 'NDQA201303001'
GROUP BY component
I suppose that works with any query that use GROUP BY, additional info, check in the link above.