C++ allocating dynamic memory in a function - newbie question

Question

I\'m investigating a memory leak and from what I see, the problem looks like this:

int main(){
    char *cp = 0;
    func(cp);
    //code
    delete[] cp;
}

voi         


        

Answer 1

The parameter cp is a local variable of the function - changing it does not alter anything outside the function. A better way to write the function is:

char * func(){
    return new char[100];
}

And not to do directly with your question, but you should probably be using std::string and std::vector rather than dynamically allocated arrays.