ndb to_dict method does not include object's key

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不思量自难忘° 2021-01-31 11:46

I am leveraging ndb\'s to_dict method to convert an object\'s properties into a python dict. From everything I can tell, this method does not include the object\'s key or parent

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  • 2021-01-31 12:02

    Another easy way to achieve that (without having to override to_dict) is to add a ComputedProperty that returns the id, like so:

    class MyModel(ndb.Model):
    
      # this property always returns the value of self.key.id()
      uid = ndb.ComputedProperty(lambda self: self.key.id(), indexed=False)
    
      # other properties ...
    

    A ComputedProperty will be added to the result of to_dict just like any other property.

    There are just two constraints:

    1. Apparently the name of the property can not be key (since that would conflict with the actual key) and id doesn't work either.
    2. This won't work if you don't specify a key or id when you create the object.

    Also, the computed value will be written to the data store when you call put(), so it consumes some of your storage space.

    An advantage is that this supports the include and exclude arguments of to_dict() out of the box.

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  • 2021-01-31 12:13

    You're not missing anything ;-)

    Just add the key to the dictionary after you call to_dict, and yes override the method.

    If you have multiple models that don't share the same base class with your custom to_dict, I would implement it as a mixin.

    to define to_dict as a method of a Mixin class. you would

    class ModelUtils(object):
        def to_dict(self):
            result = super(ModelUtils,self).to_dict()
            result['key'] = self.key.id() #get the key as a string
            return result
    

    Then to use it.

    class MyModel(ModelUtils,ndb.Model):
        # some properties etc...
    
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