The Django doc tell me how to add an option to my django custom management command, via an example:
from optparse import make_option
class Command(BaseCommand):
A little suggestion about defining the commands (key name, dest
) and handling default values (in make_option
and in the command):
class Command(BaseCommand):
option_list = BaseCommand.option_list + (
make_option('--del',
action='store_true',
help='Delete all polls.',
dest='your_name_for_delete',
default=False),
make_option('--close',
action='store_true',
help='Close all polls.'),
)
def handle(self, close, *args, **options):
if options.get('your_name_for_delete'):
Poll.objects.delete()
if options.get('close', False):
Poll.objects.update(closed=True)
In Django code you'll find "keyword arguments" (**kwargs
) often named as **options
, which is more suggestive (I stick to this naming convention).
The default value can be either specified in make_option, or through the dict.get
method,
which allows for a default value.
There's no reason not u use both defaults, should your Command.handle
method be called manually, where the **options
dictionary could be missing this entry.
You can do it like this:
from optparse import make_option
class Command(BaseCommand):
option_list = BaseCommand.option_list + (
make_option('--del',
action='store_true',
help='Delete poll'),
make_option('--close',
action='store_true',
help='Close poll'),
)
def handle(self, close, *args, **kwargs):
del_ = kwargs.get('del')
Do note that some keywords in Python are reserved so you can handle those using **kwargs
. Otherwise you can use normal arguments (like I did with close
)