How to replicate map, filter and reduce behaviors in C++ using STL?

Question

I suppose we can use std::transform to replicate the map behavior in C++ like this :

std::vector in = { 1 , 2 , 3 ,4 }; 
std::vector out(i         


        

Answer 1

Depends which container you use.

std::back_inserter will work only if the container has a push_back function.

For example back_insterter can't be used with forward_list.

In that case we need to have the memory allocated before we call std::transform on the same and first approach is better.

Answer 2

You can use std::transform to do mapping, and std::copy_if for filtering.

You have two options for reduce depending on your input and if you want to use a specific type of execution model. I've written some simple examples below to demonstrate common use cases. Note that there are multiple overloads for all these algorithms that you should use depending on your needs.

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1. std::transform

Squaring a vector of integers in place:

std::vector<int> nums{1,2,3,4};
auto unary_op = [](int num) {return std::pow(num, 2);};
std::transform(nums.begin(), nums.end(), nums.begin(), unary_op);
// nums: 1, 4, 9, 16

2. std::copy_if

Filtering odd numbers only from a vector of integers:

std::vector<int> nums{1,2,3,4};
std::vector<int> odd_nums;
auto pred = [](int num) {return num & 1;};
std::copy_if(nums.begin(), nums.end(), std::back_inserter(odd_nums), pred);
// odd_nums: 1, 3

3. std::reduce

Sum of integers in the vector starting from 0 using parallel execution model. This is really useful if, for example, you are doing a reduce operation on a really big list. Reckon that the binary operator in this case ("+") is associate and commutative, otherwise the behavior would've been non-deterministic. This is really important. The reduce operation is out-of-order if the execution model is not sequential. Only available since C++17.

std::vector<int> nums{1,2,3,4};
auto binary_op = [](int num1, int num2){return num1 + num2;};
int result = std::reduce(std::execution::par, nums.begin(), nums.end(), 0, binary_op);
// result: 10

4. std::accumulate

Same as reduce except it doesn't support execution model and the reduce operation is done in-order.

std::vector<int> nums{1,2,3,4};
auto binary_op = [](int num1, int num2){return num1 + num2;};
int result = std::accumulate(nums.begin(), nums.end(), 0, binary_op);
// result: 10