Define an Extension Method for IEnumerable which returns IEnumerable?

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情话喂你
情话喂你 2021-01-31 08:54

How do I define an Extension Method for IEnumerable which returns IEnumerable? The goal is to make the Extension Method available for

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  • 2021-01-31 09:32

    The easiest way to write any iterator is with an iterator block, for example:

    static IEnumerable<T> Where<T>(this IEnumerable<T> data, Func<T, bool> predicate)
    {
        foreach(T value in data)
        {
            if(predicate(value)) yield return value;
        }
    }
    

    The key here is the "yield return", which turns the method into an iterator block, with the compiler generating an enumerator (IEnumerator<T>) that does the same. When called, generic type inference handles the T automatically, so you just need:

    int[] data = {1,2,3,4,5};
    var odd = data.Where(i=>i%2 != 0);
    

    The above can be used with anonymous types just fine.

    You can, of coure, specify the T if you want (as long as it isn't anonymous):

    var odd = data.Where<int>(i=>i%2 != 0);
    

    Re IEnumerable (non-generic), well, the simplest approach is for the caller to use .Cast<T>(...) or .OfType<T>(...) to get an IEnumerable<T> first. You can pass in this IEnumerable in the above, but the caller will have to specify T themselves, rather than having the compiler infer it. You can't use this with T being an anonymous type, so the moral here is: don't use the non-generic form of IEnumerable with anonymous types.

    There are some slightly more complex scenarios where the method signature is such that the compiler can't identify the T (and of course you can't specify it for anonymous types). In those cases, it is usually possible to re-factor into a different signature that the compiler can use with inference (perhaps via a pass-thru method), but you'd need to post actual code to provide an answer here.


    (updated)

    Following discussion, here's a way to leverage Cast<T> with anonymous types. The key is to provide an argument that can be used for the type inference (even if the argument is never used). For example:

    static void Main()
    {
        IEnumerable data = new[] { new { Foo = "abc" }, new { Foo = "def" }, new { Foo = "ghi" } };
        var typed = data.Cast(() => new { Foo = "never used" });
        foreach (var item in typed)
        {
            Console.WriteLine(item.Foo);
        }
    }
    
    // note that the template is not used, and we never need to pass one in...
    public static IEnumerable<T> Cast<T>(this IEnumerable source, Func<T> template)
    {
        return Enumerable.Cast<T>(source);
    }
    
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  • 2021-01-31 09:39
    using System;
    using System.Collections.Generic;
    
    namespace ExtentionTest {
        class Program {
            static void Main(string[] args) {
    
                List<int> BigList = new List<int>() { 1,2,3,4,5,11,12,13,14,15};
                IEnumerable<int> Smalllist = BigList.MyMethod();
                foreach (int v in Smalllist) {
                    Console.WriteLine(v);
                }
            }
    
        }
    
        static class EnumExtentions {
            public static IEnumerable<T> MyMethod<T>(this IEnumerable<T> Container) {
                int Count = 1;
                foreach (T Element in Container) {
                    if ((Count++ % 2) == 0)
                        yield return Element;
                }
            }
        }
    }
    
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  • 2021-01-31 09:54

    This post may help you to get started:How do you write a C# Extension Method for a Generically Typed Class. I'm not sure if it is exactly what you are looking for but it might get you started.

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