Is the following snipplet correct for un-defining all otherwise generated methods and constructors for a class?
struct Picture {
// \'explicit\': no accidenta
In addition to Xeo's answer:
Yes, everything is correct. If you wanted you could eliminate all of the deleted members but the deleted copy constructor and deleted copy assignment and have the same effect:
struct Picture { // Also ok
// 'explicit': no accidental cast from string to Picture
explicit Picture(const string &filename) { /* load image from file */ }
// no copy
Picture(const Picture&) = delete;
// no assign
Picture& operator=(const Picture&) = delete;
};
The explicit declaration of the copy constructor inhibits the implicit generation of the default constructor, move constructor and move assignment members. Having these members explicitly deleted is a matter of taste. Some will probably see it as good documentation. Others may see it as overly verbose.
Seems fine to me. The return value of operator=
must be a normal reference, even if the object is constructed from a rvalue reference. That is because you can't just compile an lvalue (*this
) to an rvalue.
And it should take that rvalue reference per non-const Picture& operator=(Picture&&)
. How would you move from a constant object? ;)