I need to find an element position in an std::vector to use it for referencing an element in another vector:
int find( const vector& whe
std::vector
has random-access iterators. You can do pointer arithmetic with them. In particular, this my_vec.begin() + my_vec.size() == my_vec.end()
always holds. So you could do
const vector<type>::const_iterator pos = std::find_if( firstVector.begin()
, firstVector.end()
, some_predicate(parameter) );
if( position != firstVector.end() ) {
const vector<type>::size_type idx = pos-firstVector.begin();
doAction( secondVector[idx] );
}
As an alternative, there's always std::numeric_limits<vector<type>::size_type>::max()
to be used as an invalid value.
You could use std::numeric_limits<size_t>::max()
for elements that was not found. It is a valid value, but it is impossible to create container with such max index. If std::vector
has size equal to std::numeric_limits<size_t>::max()
, then maximum allowed index will be (std::numeric_limits<size_t>::max()-1)
, since elements counted from 0.
In this case, it is safe to cast away the unsigned portion unless your vector can get REALLY big.
I would pull out the where.size() to a local variable since it won't change during the call. Something like this:
int find( const vector<type>& where, int searchParameter ){
int size = static_cast<int>(where.size());
for( int i = 0; i < size; i++ ) {
if( conditionMet( where[i], searchParameter ) ) {
return i;
}
}
return -1;
}
Something like this, I think. find_if_counted.hpp
:
#ifndef FIND_IF_COUNTED_HPP
#define FIND_IF_COUNTED_HPP
#include <algorithm>
namespace find_if_counted_impl
{
template <typename Func>
struct func_counter
{
explicit func_counter(Func& func, unsigned &count) :
_func(func),
_count(count)
{
}
template <typename T>
bool operator()(const T& t)
{
++_count;
return _func(t);
}
private:
Func& _func;
unsigned& _count;
};
}
// generic find_if_counted,
// returns the index of the found element, otherwise returns find_if_not_found
const size_t find_if_not_found = static_cast<size_t>(-1);
template <typename InputIterator, typename Func>
size_t find_if_counted(InputIterator start, InputIterator finish, Func func)
{
unsigned count = 0;
find_if_counted_impl::func_counter<Func> f(func, count);
InputIterator result = find_if(start, finish, f);
if (result == finish)
{
return find_if_not_found;
}
else
{
return count - 1;
}
}
#endif
Example:
#include "find_if_counted.hpp"
#include <cstdlib>
#include <iostream>
#include <vector>
typedef std::vector<int> container;
int rand_number(void)
{
return rand() % 20;
}
bool is_even(int i)
{
return i % 2 == 0;
}
int main(void)
{
container vec1(10);
container vec2(10);
std::generate(vec1.begin(), vec1.end(), rand_number);
std::generate(vec2.begin(), vec2.end(), rand_number);
unsigned index = find_if_counted(vec1.begin(), vec1.end(), is_even);
if (index == find_if_not_found)
{
std::cout << "vec1 has no even numbers." << std::endl;
}
else
{
std::cout << "vec1 had an even number at index: " << index <<
" vec2's corresponding number is: " << vec2[index] << std::endl;
}
}
Though I feel like I'm doing something silly... :X Any corrections are welcome, of course.
Take a vector of integer and a key (that we find in vector )....Now we are traversing the vector until found the key value or last index(otherwise).....If we found key then print the position , otherwise print "-1".
#include <bits/stdc++.h>
using namespace std;
int main()
{
vector<int>str;
int flag,temp key, ,len,num;
flag=0;
cin>>len;
for(int i=1; i<=len; i++)
{
cin>>key;
v.push_back(key);
}
cin>>num;
for(int i=1; i<=len; i++)
{
if(str[i]==num)
{
flag++;
temp=i-1;
break;
}
}
if(flag!=0) cout<<temp<<endl;
else cout<<"-1"<<endl;
str.clear();
return 0;
}
Take a look at the answers provided for this question: Invalid value for size_t?. Also you can use std::find_if with std::distance to get the index.
std::vector<type>::iterator iter = std::find_if(vec.begin(), vec.end(), comparisonFunc);
size_t index = std::distance(vec.begin(), iter);
if(index == vec.size())
{
//invalid
}