how to get the same day of next month of a given day in python using datetime

Question

i know using datetime.timedelta i can get the date of some days away form given date

daysafter = datetime.date.today() + datetime.timedelta(days=5)


        

Answer 1

import calendar, datetime

def next_month ( date ):
    """return a date one month in advance of 'date'. 
    If the next month has fewer days then the current date's month, this will return an
    early date in the following month."""
    return date + datetime.timedelta(days=calendar.monthrange(date.year,date.month)[1])

Answer 2

from calendar import mdays
from datetime import datetime, timedelta

today = datetime.now()
next_month_of_today = today + timedelta(mdays[today.month])

I don't want to import dateutil. Have a try this. Good luck.

Answer 3

Use dateutil module. It has relative time deltas:

import datetime
from dateutil import relativedelta
nextmonth = datetime.date.today() + relativedelta.relativedelta(months=1)

Beautiful.