Get the Year/Month/Day from a datetime in php?

Question

I used date(\'w\', timestamp) and date(\'w\', timestamp) to know the day, date(\'n\', timestamp) for months, etc.

Now I\'m using d

Answer 1

Check out the manual: http://www.php.net/manual/en/datetime.format.php

<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>

Will output: 2000-01-01 00:00:00

Answer 2

Try below code if you want to use php loop to display

<span>
  <select name="birth_month">
    <?php for( $m=1; $m<=12; ++$m ) { 
      $month_label = date('F', mktime(0, 0, 0, $m, 1));
    ?>
      <option value="<?php echo $month_label; ?>"><?php echo $month_label; ?></option>
    <?php } ?>
  </select> 
</span>
<span>
  <select name="birth_day">
    <?php 
      $start_date = 1;
      $end_date   = 31;
      for( $j=$start_date; $j<=$end_date; $j++ ) {
        echo '<option value='.$j.'>'.$j.'</option>';
      }
    ?>
  </select>
</span>
<span>
  <select name="birth_year">
    <?php 
      $year = date('Y');
      $min = $year - 60;
      $max = $year;
      for( $i=$max; $i>=$min; $i-- ) {
        echo '<option value='.$i.'>'.$i.'</option>';
      }
    ?>
  </select>
</span>

Answer 3

Use DateTime with DateTime::format()

$datetime = new DateTime($dateTimeString);
echo $datetime->format('w');