How to split a string in Ruby and get all items except the first one?

Question

String is ex=\"test1, test2, test3, test4, test5\"

when I use

ex.split(\",\").first

it returns

\"test1\"
         


        

Answer 1

Sorry a bit late to the party and a bit surprised that nobody mentioned the drop method:

ex="test1, test2, test3, test4, test5"
ex.split(",").drop(1).join(",")
=> "test2,test3,test4,test5"

Answer 2

You can also do this:

String is ex="test1, test2, test3, test4, test5"
array = ex.split(/,/)
array.size.times do |i|
  p array[i]
end 

Answer 3

Try split(",")[i] where i is the index in result array. split gives array below

["test1", " test2", " test3", " test4", " test5"] 

whose element can be accessed by index.

Answer 4

if u want to use them as an array u already knew, else u can use every one of them as a different parameter ... try this :

parameter1,parameter2,parameter3,parameter4,parameter5 = ex.split(",")

Answer 5

ex="test1,test2,test3,test4,test5"
all_but_first=ex.split(/,/)[1..-1]

Answer 6

ex.split(',', 2).last

The 2 at the end says: split into 2 pieces, not more.

normally split will cut the value into as many pieces as it can, using a second value you can limit how many pieces you will get. Using ex.split(',', 2) will give you:

["test1", "test2, test3, test4, test5"]

as an array, instead of:

["test1", "test2", "test3", "test4", "test5"]