Java - parse String and add Line break every 100 characters [duplicate]

Answer 1

As you cannot just add more charachters to a regular String in Java. You should use the StringBuffer to do this.

You can loop through the String with a for loop and then so something after every 100th character:

String string = "Some long string ...";
StringBuffer buffer = new StringBuffer();

for(int i = 0; i < string.length(); i++) {
    // Append a \n after every 100th character.
    if((i > 0) && (i % 100) == 0) {
        buffer.append("\n");
    }
    // Just adds the next character to the StringBuffer.
    buffer.append(string.charAt(i));
}

String parsedString = buffer.toString();

Answer 2

I suggest using StringBuilder. It is efficient and can suit your task exactly.

String originalString = ... ;

// The new length of the string is
int newLength = originalString.length() +(int) Math.ceil ( originalString.length() / 100.0 );

StringBuilder builder = new StringBuilder ( newLength );

I'll refer to each 100 character part of the string as a "chunk" so that its easy to see what's going on.

int chunkStart = 0;

while ( chunkStart < originalString.length() )
{
    // We find the index of the end of the chunk.
    int endOfThisChunk = Math.min ( chunkStart + 100, originalString.length() );

    // and this chunk to builder
    builder.append ( originalString.substring( chunkStart, endOfThisChunk ) );

    // append the new line character
    builder.append ( '\n' );

    // set the next spot for chunkStart
    chunkStart = endOfThisChunk;
}

return builder.toString();

Hope that helps! If you need more explanation please let me know!

Answer 3

i think this is a bit faster than % 100 and repeatedly appending

function(String input) {
    // array represantation of the String
    final char[] inputArray = input.toCharArray();
    // same length + amount of newlines (i.e. length / 100)
    final char[] outputArray = new char[inputArray.length + (inputArray.length/100)];
    int i = 0;
    int o = 0;
    while(i < inputArray.length) {
        // copy every 100th substring
        System.arraycopy(inputArray,i,outputArray,o,100);
        i += 100;
        o += 101;
        outputArray[o] = '\n';
    }
    // copy rest
    if(i < inputArray.length) {
        System.arraycopy(inputArray,i,outputArray,o,inputArray.length-i);
    }
    return(outputArray.toString());
}

though untested

Answer 4

There is no need to parse the String via regex, you can just split it.

String s = "your very long String";
String[] splited = new String[s.size() / 100 + 1];
for (int i = 0; i < splited.length(); i++) {
  splited[i] = s.subString(0, 100);
  s = s.subString(100);
}

EDIT

StringBuilder sb = new StringBuilder();
for(int i = 0; i< splited.size(); i++) {
  sb.append(splited[i]);
  sb.append("\n");
}
String stringWithNewLines = sb.toString();

Answer 5

You could do something like so:

String str = "....";
String parsedStr = str.replaceAll("(.{100})", "$1\n");

This will replace every 100 characters with the same 100 characters and add a new line at the end.

The (.{100}) will capture a group of 100 characters. The $1 in the second will put the content of the group. The \n will be then appended to the 100 characters which have been just matched.

Answer 6

Quite simply:

StringBuilder sb = new StringBuilder();
for (int i = 0; i < str.length(); i++) {
    if (i > 0 && (i % 100 == 0)) {
        sb.append("\n");
    }

    sb.append(str.charAt(i));
}

str = sb.toString();