I understand what tapply() does in R. However, I cannot parse this description of it from the documentaion:
Apply a Function Over a \"Ragged\" Array Description:
@joran's great answer helped me understand it (so please vote for his - I would have added it as comment if it wasn't too long for that), but this may be of help to some:
In quite a few languages, you have twodimensional arrays. Depending on the language, these arrays have fixed dimensions (i.e.: each row has the same number of columns), or some languages allow the number of items per row to differ. So instead of:
A: 1 2 3
B: 4 5 6
C: 7 8 9
You could get something like
A: 1 3
B: 4 5 6
C: 8
This is called a ragged array because, well, the right side of it looks ragged. In typical R-style, we might represent this as two vectors:
values<-c(1,3,4,5,6,8)
names<-c("A", "A", "B", "B", "B", "C")
So tapply
with these two vectors as the first parameters indeed allows us to apply this function to each 'row' of our ragged array.
Let's see what the R documentation says on the subject:
The combination of a vector and a labelling factor is an example of what is sometimes called a ragged array, since the subclass sizes are possibly irregular. When the subclass sizes are all the same the indexing may be done implicitly and much more efficiently, as we see in the next section.
The list of factors you supply via INDEX
together specify a collection of subsets of X
, of possibly different lengths (hence, the 'ragged' descriptor). And then FUN
is applied to each subset.
EDIT: @Joris makes an excellent point in the comments. It may be helpful to think of tapply(X,Y,...)
as a wrapper for sapply(split(X,Y),...)
in that if Y is a list of grouping factors, it builds a new, single grouping factor based on their unique levels, splits X accordingly and applies FUN to each piece.
EDIT: Here's an illustrative example:
library(lattice)
library(plyr)
set.seed(123)
#Make this example unbalanced
dat <- barley[sample(1:120,50),]
#Suppose we want the avg yield by year/site:
table(dat$year,dat$site)
#That's what they mean by 'ragged' array; there are different
# numbers of obs at each comb of levels
#In plyr we could use ddply:
ddply(dat,.(year,site),.fun=function(x){mean(x$yield)})
#Which gives the same result (listed in a diff order) as:
melt(tapply (dat$yield, list (dat$year, dat$site), mean))