I\'m using sqlite3 in python 2.5. I\'ve created a table that looks like this:
create table votes (
bill text,
senator_id text,
vote text)
<
I was recently trying to do something similar while using sqlite3.Row(). While sqlite3.Row() is great for providing a dictionary-like interface or a tuple like interface, it didn't work when I piped in the row using **kwargs. So, needed a quick way of converting it to a dictionary. I realised that the Row() object can be converted to a dictionary simply by using itertools.
Python 2:
db.row_factory = sqlite3.Row
dbCursor = db.cursor()
dbCursor.execute("SELECT * FROM table")
row = dbCursor.fetchone()
rowDict = dict(itertools.izip(row.keys(), row))
Or in Python 3, more simply:
dbCursor = db.cursor()
dbCursor.execute("SELECT * FROM table")
row = dbCursor.fetchone()
rowDict = dict(zip([c[0] for c in dbCursor.description], row))
Similarly, you can use the dbCursor.fetchall() command and convert the entire set of rows to a list of dictionaries in a for loop.
The way I've done this in the past:
def dict_factory(cursor, row):
d = {}
for idx,col in enumerate(cursor.description):
d[col[0]] = row[idx]
return d
Then you set it up in your connection:
from pysqlite2 import dbapi2 as sqlite
conn = sqlite.connect(...)
conn.row_factory = dict_factory
This works under pysqlite-2.4.1 and python 2.5.4.