In emacs, how to strip CR (^M) and leave LF (^J) characters?

Question

I am trying to use hexl mode to manually remove some special chars from a text file and don\'t see how to delete anything in hexl mode.

What I really want is to remove c

Answer 1

Oops. That ^J^M needs to be entered as two literal characters. Use c-q c-j, c-q c-m and for the replacement string, use c-q c-j.

Answer 2

No need for hexl-mode for this. Just do a global-search-and-replace of ^J^M with ^J Works for me. :) Then save the file, kill the buffer, and revisit the file so the window shows the new file mode (Unix vs DOS).

Answer 3

From http://www.xsteve.at/prg/emacs/xsteve-functions.el:

;02.02.2000
(defun xsteve-remove-control-M ()
  "Remove ^M at end of line in the whole buffer."
  (interactive)
  (save-match-data
    (save-excursion
      (let ((remove-count 0))
        (goto-char (point-min))
        (while (re-search-forward (concat (char-to-string 13) "$") (point-max) t)
          (setq remove-count (+ remove-count 1))
          (replace-match "" nil nil))
        (message (format "%d ^M removed from buffer." remove-count))))))

Add this to your .emacs and run it via M-x xsteve-remove-control-M or bind it to a easier key. It will strip the ^Ms in anymode.

Answer 4

I use this function:

(defun l/cr-sanitise ()
  "Make sure current buffer uses unix-utf8 encoding.
If necessary remove superfluous ^M. Buffer will need to be saved
for changes to be permanent."
  (interactive)
    (set-buffer-file-coding-system 'utf-8-unix)
    (delete-trailing-whitespace)
    (message "Please save buffer to persist encoding changes."))