Html5 video recording and upload?

Question

I need to create an app that can record video using a webcam or mobile camera (it needs to be cross platform).

So far I have written a small proof of concept using webrt

Answer 1

You can record video and audio separately. You can get files (WAV/WebM) and upload them on demand. webkitMediaStream takes two objects 1) audioTracks and 2) videoTracks. You may be able to combine both audio/video recorded streams!

Answer 2

I know I'm a few years late to the party, but here is a snippet that's capable of capturing video and uploading it to the included node.js server as a webm file. I've tested in Chrome and Firefox.

https://gist.github.com/rissem/d51b1997457a7f6dc4cf05064f5fe984

Answer 3

The only cross platform web video recorder is the HDFVR webcam video recorder software.

It uses Flash (records using Flash codecs + streams to a media server) on the desktop and the HTML Media Capture API (record using OS + upload to webserver) on mobile to record video from pretty much any desktop or mobile browser.

You can link it to a ffmpeg installation to convert everything to a cross platform format like MP4 (iOS records to a .mov container that doesn't play on Android) and it also has a JS API.

Answer 4

Hi sorry if this is kinda late, but here is how i managed to make the file upload to a server, I really don't have an idea if this is the best way to achieve this but i hope it helps to give you a clue.Following the tutorial Eric Bidelman wrote (as Sam Dutton commented) what you get is a blob, so I made a XMLHttpRequest to get the video and set the response type as blob, afterwards I created a FormData in which I appended the response, this will allow the blob to be sent to the server.Here is how my function looks like.

function sendXHR(){
    //Envia bien blob, no interpretado
    var xhr = new XMLHttpRequest();
    var video=$("#myexportingvideo");
    xhr.open('GET', video.src , true);
    xhr.responseType = 'blob';
    xhr.onload = function(e) {
    if (this.status == 200) {
        // Note: .response instead of .responseText
        var blob = new Blob([this.response], {type: 'video/webm'});
        console.log(blob.size/1024);
        console.log(blob.type);
        form = new FormData(),
        request = new XMLHttpRequest();
        form.append("myblob",blob,"Capture.webm");
        form.append("myname",$("#name_test").value);
        request.open("POST","./UploadServlet",true);
        request.send(form);
       }
    };
    xhr.send();
}