SQL query for finding the longest name and shortest name in a table

Question

I have a table with one of the columns is of type varchar(city). and want to find the longest and shortest of values stored in that column.

select a.city, a.city         


        

Answer 1

select city,length(city) from (select city,length(city),rank() over(partition by length(city) order by length(city),city asc) as rnk from station)a where a.rnk=1;

Answer 2

select top(1) city, max(len(city)) [Length] from station group by city order by [Length]
select top(1) city, max(len(city)) [Length] from station group by city order by [Length] DESC

Tested in SQL Server 2016

Answer 3

In Oracle:

select * from (select city, min(length(city)) minl from station group by city order by minl, city) where rownum = 1;
select * from (select city, max(length(city)) maxl from station group by city order by maxl desc, city) where rownum = 1;

Answer 4

In Oracle it would be,

SELECT CITY,LENGTH(CITY) FROM   (SELECT MIN(CITY) CITY  FROM STATION WHERE LENGTH(CITY)=(SELECT MIN(LENGTH(CITY)) FROM STATION))
UNION ALL
SELECT CITY,LENGTH(CITY) FROM   (SELECT MAX(CITY) CITY  FROM STATION WHERE LENGTH(CITY)=(SELECT MAX(LENGTH(CITY)) FROM STATION));    

Answer 5

Shortest:

select TOP 1 CITY,LEN(CITY) LengthOfCity FROM STATION ORDER BY LengthOfCity ASC, CITY ASC;

Longest:

select TOP 1 CITY,LEN(CITY) LengthOfCity FROM STATION ORDER BY LengthOfCity DESC, CITY ASC;

This works for HackerRank challenge problem (MS SQL Server).