Highest Salary in each department

Question

I have a table EmpDetails:

DeptID      EmpName   Salary
Engg        Sam       1000
Engg        Smith     2000
HR          Denis     1500
HR                  


        

Answer 1

SELECT empName,empDept,EmpSalary
FROM Employee
WHERE empSalary IN
  (SELECT max(empSalary) AS salary
   From Employee
   GROUP BY EmpDept)

Answer 2

SELECT Employee_ID
     , First_name
     , last_name
     , department_id
     , Salary 
FROM (SELECT Employee_ID
           , First_name
           , last_name
           , department_id
           , Salary
           , MAX(salary) OVER (PARTITION BY department_id) dept_max_sal
      FROM EMPLOYEES) AS Emp
WHERE salary = dept_max_sal;

Answer 3

Use following command;

SELECT  A.*
    FROM    @EmpDetails A
            INNER JOIN ( SELECT DeptID ,
                                MAX(salary) AS salary
                         FROM   @EmpDetails
                         GROUP BY DeptID
                       ) B ON A.DeptID = B.DeptID
                              AND A.salary = B.salary
    ORDER BY A.DeptID

Answer 4

select * from (
    select a.* from EmpDetails a 
    right join (select DeptID,max(salary) as Salary from EmpDetails group by DeptID) b
    on b.DeptID=a.DeptID and b.salary=a.salary ) as c  group by c.DeptID;

Answer 5

SELECT empname
FROM empdetails
WHERE salary IN(SELECT deptid max(salary) AS salary
FROM empdetails
group by deptid)

Answer 6

Assuming SQL Server 2005+

WITH cteRowNum AS (
    SELECT DeptID, EmpName, Salary,
           DENSE_RANK() OVER(PARTITION BY DeptID ORDER BY Salary DESC) AS RowNum
        FROM EmpDetails
)
SELECT DeptID, EmpName, Salary
    FROM cteRowNum
    WHERE RowNum = 1;