UNION
joins two results and remove duplicates, while UNION ALL
does not remove duplicates.
UNION
also sort the final output.
W
SELECT *, 1 AS sort_order
FROM table1
EXCEPT
SELECT *, 1 AS sort_order
FROM table2
UNION
SELECT *, 1 AS sort_order
FROM table1
INTERSECT
SELECT *, 1 AS sort_order
FROM table2
UNION
SELECT *, 2 AS sort_order
FROM table2
EXCEPT
SELECT *, 2 AS sort_order
FROM table1
ORDER BY sort_order;
But the real answer is: other than the ORDER BY
clause, the sort order will by arbitrary and not guaranteed.
I assume your tables are table1 and table2 respectively, and your solution is;
(select * from table1 MINUS select * from table2)
UNION ALL
(select * from table2 MINUS select * from table1)
Try this:
SELECT DISTINCT * FROM (
SELECT column1, column2 FROM Table1
UNION ALL
SELECT column1, column2 FROM Table2
UNION ALL
SELECT column1, column2 FROM Table3
) X ORDER BY Column1
"UNION also sort the final output" - only as an implementation artifact. It is by no means guaranteed to perform the sort, and if you need a particular sort order, you should specify it with an ORDER BY
clause. Otherwise, the output order is whatever is most convenient for the server to provide.
As such, your request for a function that performs a UNION ALL
but that removes duplicates is easy - it's called UNION
.
From your clarification, you also appear to believe that a UNION ALL
will return all of the results from the first query before the results of the subsequent queries. This is also not guaranteed. Again, the only way to achieve a particular order is to specify it using an ORDER BY
clause.
1,1:
select 1 from dual
union all select 1 from dual
1:
select 1 from dual
union select 1 from dual
I notice this question gets quite a lot of views so I'll first address a question you didn't ask!
Regarding the title. To achieve a "Sql Union All with “distinct”" then simply replace UNION ALL
with UNION
. This has the effect of removing duplicates.
For your specific question, given the clarification "The first query should have "priority", so duplicates should be removed from bottom" you can use
SELECT col1,
col2,
MIN(grp) AS source_group
FROM (SELECT 1 AS grp,
col1,
col2
FROM t1
UNION ALL
SELECT 2 AS grp,
col1,
col2
FROM t2) AS t
GROUP BY col1,
col2
ORDER BY MIN(grp),
col1