Setting ruby hash .default to a list [duplicate]

Answer 1

irb(main):002:0> a.default = []
=> []
irb(main):003:0> a[8] << 9
=> [9]                          # great!

With this statement, you have modified the default; you have not created a new array and added "9". At this point, it's identical to if you had done this instead:

irb(main):002:0> a.default = [9]
=> [9]

Hence it's no surprise that you now get this:

irb(main):006:0> a[9]
=> [9]                          # unawesome! shouldn't this be [] ??

Furthermore, the '<<' added the '9' to the array; it did not add it to the hash, which explains this:

irb(main):004:0> a
=> {}                           # ?! would have expected {8=>[9]}

Instead of using .default, what you probably want to do in your program is something like this:

# Time to add a new entry to the hash table; this might be 
# the first entry for this key..
myhash[key] ||= []
myhash[key] << value

Answer 2

I'm not sure if this is what you want, but you can do this to always return an empty array when a missing hash key is queried.

h = Hash.new { [] }
h[:missing]
   => []

#But, you should never modify the empty array because it isn't stored anywhere
#A new, empty array is returned every time
h[:missing] << 'entry'
h[:missing]
   => []

Answer 3

This is a very useful idiom:

(myhash[key] ||= []) << value

It can even be nested:

((myhash[key1] ||= {})[key2] ||= []) << value

The other way is to do:

myhash = Hash.new {|hash,key| hash[key] = []}

But this has the significant side-effect that asking about a key will create it, which renders has_key? fairly useless, so I avoid this method.

Answer 4

Hash.default is used to set the default value returned when you query a key that doesn't exist. An entry in the collection is not created for you, just because queried it.

Also, the value you set default to is an instance of an object (an Array in your case), so when this is returned, it can be manipulated.

a = {}
a.default = []     # set default to a new empty Array
a[8] << 9          # a[8] doesn't exist, so the Array instance is returned, and 9 appended to it
a.default          # => [9]
a[9]               # a[9] doesn't exist, so default is returned

Answer 5

I think this is the behavior you are looking for. This will automatically initialize any new keys in the Hash to an array:

irb(main):001:0> h = Hash.new{|h, k| h[k] = []}
=> {}
irb(main):002:0> h[1] << "ABC"
=> ["ABC"]
irb(main):003:0> h[3]
=> []
irb(main):004:0> h
=> {1=>["ABC"], 3=>[]}

Answer 6

If you really wanna have an endlessly deep hash:

endless = Hash.new { |h, k| h[k] = Hash.new(&h.default_proc) }
endless["deep"]["in"]["here"] = "hello"

Of course, as Glenn points out above, if you do this, the has_key? looses its meaning as it will always return true. Thx to jbarnette for this one.