Get element of JS object with an index

Question

Ok so let\'s say that I have my object

myobj = {\"A\":[\"Abe\"], \"B\":[\"Bob\"]}

and I want to get the first element out of it. As in I want i

Answer 1

JS objects have no defined order, they are (by definition) an unsorted set of key-value pairs.

If by "first" you mean "first in lexicographical order", you can however use:

var sortedKeys = Object.keys(myobj).sort();

and then use:

var first = myobj[sortedKeys[0]];

Answer 2

I know it's a late answer, but I think this is what OP asked for.

myobj[Object.keys(myobj)[0]];

Answer 3

If you want a specific order, then you must use an array, not an object. Objects do not have a defined order.

For example, using an array, you could do this:

var myobj = [{"A":["B"]}, {"B": ["C"]}];
var firstItem = myobj[0];

Then, you can use myobj[0] to get the first object in the array.

Or, depending upon what you're trying to do:

var myobj = [{key: "A", val:["B"]}, {key: "B",  val:["C"]}];
var firstKey = myobj[0].key;   // "A"
var firstValue = myobj[0].val; // "["B"]

Answer 4

Object.keys(city)[0];   //return the key name at index 0
Object.values(city)[0]  //return the key values at index 0

Answer 5

myobj.A

------- or ----------

myobj['A']

will get you 'B'

Answer 6

I Hope that will help

$.each(myobj, function(index, value) { 

    console.log(myobj[index]);

   )};