Why does field declaration with duplicated nested type in generic class results in huge source code increase?

后端 未结 3 1413
后悔当初
后悔当初 2021-01-30 16:53

Scenario is very rare, but quite simple: you define a generic class, then create a nested class which inherits from outer class and define a associative field (of self type) wit

相关标签:
3条回答
  • 2021-01-30 17:13

    This is not an answer!

    There are many aspects of your question. A little one is: If a type contains (because of inheritance, not allowed otherwise) a nested type with the same name as the type itself, and if that name is used inside the type, what does the name refer to?

    It's hard to express in words, but here's the example I have in mind:

    namespace N
    {
      class Mammal
      {
        // contains nested type of an unfortunate name
        internal interface Giraffe
        {
        }
      }
    
      class Giraffe : Mammal
      {
        Giraffe g;  // what's the fully qualified name of the type of g?
      }
    }
    

    Note: This is easy! No generics! No problem with a class inheriting its own containing class.

    The question here is, what is the type of g? Is it N.Giraffe (a class), or is it N.Giraffe.Giraffe (an interface)? The correct answer is the latter. Because to find a meaning for the name Giraffe, one first searches the members of the current type (in this case one finds the interface). Only if no match is found there, one proceeds to the members of the current namespace (where the current type would be found).

    0 讨论(0)
  • 2021-01-30 17:24

    The core of your question is why Inner.Inner is a different type than Inner. Once you understand that, your observations about compile time and generated IL code size follow easily.

    The first thing to note is that when you have this declaration

    public class X<T>
    {
      public class Y { }
    }
    

    There are infinitely many types associated with the name Y. There is one for each generic type argument T, so X<int>.Y is different than X<object>.Y, and, important for later, X<X<T>>.Y is a different type than X<T>.Y for all T's. You can test this for various types T.

    The next thing to note is that in

    public class A
    {
      public class B : A { }
    }
    

    There are infinitely many ways to refer to nested type B. One is A.B, another is A.B.B, and so on. The statement typeof(A.B) == typeof(A.B.B) returns true.

    When you combine these two, the way you have done, something interesting happens. The type Outer<T>.Inner is not the same type as Outer<T>.Inner.Inner. Outer<T>.Inner is a subclass of Outer<Outer<T>.Inner> while Outer<T>.Inner.Inner is a subclass of Outer<Outer<Outer<T>.Inner>.Inner>, which we established before as being different from Outer<T>.Inner. So Outer<T>.Inner.Inner and Outer<T>.Inner are referring to different types.

    When generating IL, the compiler always uses fully qualified names for types. You have cleverly found a way to refer to types with names whose lengths that grow at exponential rates. That is why as you increase the generic arity of Outer or add additional levels .Y to the field field in Inner the output IL size and compile time grow so quickly.

    0 讨论(0)
  • 2021-01-30 17:32

    Inheriting from a generic parameterized with the current type is often called Curiously recurring template pattern and is discouraged by Eric Lippert, previously on the C# compiler team.

    In your case, the nested class Outer<A>.Inner is defined as inheriting from Outer<Inner>. That means the nested class contains, through inheritance, a definition of a nested class. This yields an infinite definition of nested classes: Outer<A>.Inner.Inner.Inner...

    Now, in your original definition

    class Inner : Outer<Inner>
    {
        Inner field;
    }
    

    the field is declared as type Inner which in this scope refers to the current type being defined. When you changed it to Inner.Inner, the first Inner referred to the current type being defined and the second .Inner referred to the nested class obtained through inheritance.

    As an example, let's expand the definition of the Inner class to include what is coming from the inheritance (and renaming to make things a little clearer):

    //original
    class Outer<A>
    {
        class Inner1 //: Outer<Inner1>
        {
            Inner1 field;
    
            //from inheritance
            class Inner2 : Outer<Inner1.Inner2>
            {
                Inner2 field;
            }
        }
    }
    
    //modified for Inner.Inner
    class Outer<A>
    {
        class Inner1 //: Outer<Inner1>
        {
            Inner1.Inner2 field;
    
            //from inheritance
            class Inner2 : Outer<Inner1.Inner2>
            {
                Inner2.Inner3 field;
            }
        }
    }
    

    So back to your questions:

    Why do we observe such behavior? Is the Inner.Inner type declaration has changed the type at all? Are Inner.Inner and Inner types differ in some way in this context?

    You changed the type definition of class Inner so that its field is of a different type. An instance of Outer<A>.Inner would possibly (I have not verified) be castable to the other Inner type but they are 2 type definitions.

    0 讨论(0)
提交回复
热议问题