I have found many ways to pop back 2 UIViewControllers
in UINavigationController
using Objective-C, however when I try and switch that over to Swift it
I wrote an UIViewController extension (Swift 3+ ready)
You could use like this :
/// pop back n viewcontroller
func popBack(_ nb: Int) {
if let viewControllers: [UIViewController] = self.navigationController?.viewControllers {
guard viewControllers.count < nb else {
self.navigationController?.popToViewController(viewControllers[viewControllers.count - nb], animated: true)
return
}
}
}
Usage :
self.popBack(3)
Bonus dismiss to a specific viewcontroller
/// pop back to specific viewcontroller
func popBack<T: UIViewController>(toControllerType: T.Type) {
if var viewControllers: [UIViewController] = self.navigationController?.viewControllers {
viewControllers = viewControllers.reversed()
for currentViewController in viewControllers {
if currentViewController .isKind(of: toControllerType) {
self.navigationController?.popToViewController(currentViewController, animated: true)
break
}
}
}
}
Usage :
self.popBack(toControllerType: MyViewController.self)
I did a helper to make it easy:
import Foundation
import UIKit
class NavigationHelper {
static func back(number: Int, from viewControlller : UIViewController) {
let viewsBack = number + 1
let viewControllers: [UIViewController] = viewControlller.navigationController!.viewControllers as [UIViewController]
viewControlller.navigationController!.popToViewController(viewControllers[viewControllers.count - viewsBack], animated: true)
}
static func back(number: Int, from viewControlller: UITableViewController) {
let viewsBack = number + 1
let viewControllers: [UIViewController] = viewControlller.navigationController!.viewControllers as [UIViewController]
viewControlller.navigationController!.popToViewController(viewControllers[viewControllers.count - viewsBack], animated: true)
}
}
For example, in your ViewController
you can use NavigationHelper.back(number: 1, from: self)
Expanding on my comment, find the second last view controller in the viewControllers array and then use popToViewController to avoid overwriting the entire view controller stack.
Example (assumes the navigation controller has more than 1 view controller):
func backTwo() {
let viewControllers: [UIViewController] = self.navigationController!.viewControllers as [UIViewController]
self.navigationController!.popToViewController(viewControllers[viewControllers.count - 3], animated: true)
}
Objective-C
NSArray *viewControllers = [self.navigationController viewControllers];
[self.navigationController popToViewController:viewControllers[viewControllers.count - 3] animated:YES];
user5320485 answer in swift3
let viewControllers = self.navigationController!.viewControllers as [UIViewController];
for aViewController:UIViewController in viewControllers {
if aViewController.isKind(of: AdCreateViewController.self) {
_ = self.navigationController?.popToViewController(aViewController, animated: true)
}
}
You can dynamically pop multiple viewcontrollers in (swift 2.0)
let allViewController: [UIViewController] = self.navigationController!.viewControllers as [UIViewController];
for aviewcontroller : UIViewController in allViewController
{
if aviewcontroller .isKindOfClass(YourDestinationViewControllerName)
{
self.navigationController?.popToViewController(aviewcontroller, animated: true)
}
}
Swift 4 UINavigationController extension version of @Maximelc's answer:
extension UINavigationController {
func popBack(_ nb: Int) {
let viewControllers: [UIViewController] = self.viewControllers
guard viewControllers.count < nb else {
self.popToViewController(viewControllers[viewControllers.count - nb], animated: true)
return
}
}
/// pop back to specific viewcontroller
func popBack<T: UIViewController>(toControllerType: T.Type) {
var viewControllers: [UIViewController] = self.viewControllers
viewControllers = viewControllers.reversed()
for currentViewController in viewControllers {
if currentViewController .isKind(of: toControllerType) {
self.popToViewController(currentViewController, animated: true)
break
}
}
}
}