Open Powershell in a specific directory from shortcut

Question

This sounds like it should be so simple... I must be dumb.

All I want is to make a windows short-cut that opens Powershell into a specific directory:

I\'m using

Answer 1

If one wants a explorer right click options run this script:

New-PSDrive -Name HKCR -PSProvider Registry -Root HKEY_CLASSES_ROOT
if(-not (Test-Path -Path "HKCR:\Directory\shell\$KeyName"))
{
    Try
    {
        New-Item -itemType String "HKCR:\Directory\shell\$KeyName" -value "Open PowerShell in this Folder" -ErrorAction Stop
        New-Item -itemType String "HKCR:\Directory\shell\$KeyName\command" -value "$env:SystemRoot\system32\WindowsPowerShell\v1.0\powershell.exe -noexit -command Set-Location '%V'" -ErrorAction Stop
        Write-Host "Successfully!"
     }
     Catch
     {
         Write-Error $_.Exception.Message
     }
}
else
{
    Write-Warning "The specified key name already exists. Type another name and try again."
}

This is what is shown now:

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Note that you can download a detailed script from how to start PowerShell from Windows Explorer.

Answer 2

try:

%SystemRoot%\system32\WindowsPowerShell\v1.0\powershell.exe 
-noexit -command "cd c:/path/to/open"

Answer 3

Copy this code into notepad and save with a reg extension. Double click the resulting file.If you get a message about importing to the registry click on yes and then ok. Navigate to any folder in explorer and bring up the context menu. This is typically done by clicking the right mouse button.

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Windows Registry Editor Version 5.00

[HKEY_CLASSES_ROOT\Directory\Background\shell\PShell]
"MUIVerb"="Open in Powershell Window"

[HKEY_CLASSES_ROOT\Directory\Background\shell\PShell\command]
@="c:\\windows\\system32\\WindowsPowerShell\\v1.0\\powershell.exe -NoExit -Command Set-Location -LiteralPath '%V'"