How to obtain a list of directories within a directory, like list.files(), but instead “list.dirs()”

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梦如初夏
梦如初夏 2021-01-30 12:14

This may be a very easy question for someone - I am able to use list.files() to obtain a list of files in a given directory, but if I want to get a list of director

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  • 2021-01-30 12:53
    list.dirs <- function(...) {
        x <- dir(...)
        x[file_test("-d", x)]
    }
    

    might be of use?

    How might we do this recursively? (the recursive argument of dir breaks these functions because it never returns directory names, just the files within each directory, etc...).

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  • 2021-01-30 12:54

    You mention that you don't want to shell out to a Linux/UNIX command but I assume its ok to shell out to a Windows command. In that case this would do it:

    shell("dir/ad/b", intern = TRUE)
    

    and this would do it recursively:

    shell("dir/ad/b/s", intern = TRUE)
    

    Normally I would prefer the platform independent solutions of others here but particularly for interactive use where you are just concerned with getting the answer as simply and directly as possible this may be less work.

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  • 2021-01-30 12:56

    I had this problem a while back and used this recursive code to find all directories. Perhaps this can be of use?

    list.dirs <- function(parent=".")   # recursively find directories
    {
        if (length(parent)>1)           # work on first and then rest
            return(c(list.dirs(parent[1]), list.dirs(parent[-1])))
        else {                          # length(parent) == 1
            if (!is.dir(parent))
                return(NULL)            # not a directory, don't return anything
            child <- list.files(parent, full=TRUE)
            if (!any(is.dir(child)))
                return(parent)          # no directories below, return parent
            else 
                return(list.dirs(child))    # recurse
        }
    }
    
    is.dir <- function(x)    # helper function
    {
        ret <- file.info(x)$isdir
        ret[is.na(ret)] <- FALSE
        ret
    }
    
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  • 2021-01-30 13:01

    What about something like this, give it a try:

    dir('.')[file.info(dir('.',full.names=T))$isdir]
    
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  • 2021-01-30 13:04

    base R now includes a list.dirs function, so home-brewed variants are no longer necessary.

    For example:

    list.dirs('.', recursive=FALSE)
    
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  • 2021-01-30 13:06

    Update: A list.dirs function was added to the base package in revision 54353, which was included in the R-2.13.0 release in April, 2011.

    list.dirs(path = ".", full.names = TRUE, recursive = TRUE)
    

    So my function below was only useful for a few months. :)


    I couldn't find a base R function to do this, but it would be pretty easy to write your own using:

    dir()[file.info(dir())$isdir]
    

    Update: here's a function (now corrected for Timothy Jones' comment):

    list.dirs <- function(path=".", pattern=NULL, all.dirs=FALSE,
      full.names=FALSE, ignore.case=FALSE) {
      # use full.names=TRUE to pass to file.info
      all <- list.files(path, pattern, all.dirs,
               full.names=TRUE, recursive=FALSE, ignore.case)
      dirs <- all[file.info(all)$isdir]
      # determine whether to return full names or just dir names
      if(isTRUE(full.names))
        return(dirs)
      else
        return(basename(dirs))
    }
    
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