log first 10 in git

Question

Two questions:

1. How to show the first 10 commit in git from beginning to end. (no branch)
2. How the specify the commit index and log it. (show the second or

Answer 1

Here my approach,

To get first 10 commits:

git log -n 10

-n is number

Additional To get next 10 commit skip first 10 :

git log --skip=10 -n 10

Answer 2

Simply log everything with one line format and tail the output:

git log  --pretty=oneline | tail -n 10 

Answer 3

In case someone wants more than just git one-line log:

git log --reverse | awk 'NR>1 {print last} {last=$0}; /^commit/ && ++c==11{exit}'

where the 11 at the end should be set to 1 more than the number of commits you want.

As here points out git log --reverse -n 10 doesn't work as you need it to. (I suppose it would need to be non-commutative to give you the ability to chose the first 10 commits in reverse order or the last 10 commits