I know du -sh
in common Linux filesystems. But how to do that with HDFS?
hadoop fs -du -s -h /path/to/dir
displays a directory's size in readable form.
Extending to Matt D and others answers, the command can be till Apache Hadoop 3.0.0
hadoop fs -du [-s] [-h] [-v] [-x] URI [URI ...]
It displays sizes of files and directories contained in the given directory or the length of a file in case it's just a file.
Options:
- The -s option will result in an aggregate summary of file lengths being displayed, rather than the individual files. Without the -s option, the calculation is done by going 1-level deep from the given path.
- The -h option will format file sizes in a human-readable fashion (e.g 64.0m instead of 67108864)
- The -v option will display the names of columns as a header line.
- The -x option will exclude snapshots from the result calculation. Without the -x option (default), the result is always calculated from all INodes, including all snapshots under the given path.
du
returns three columns with the following format: +-------------------------------------------------------------------+
| size | disk_space_consumed_with_all_replicas | full_path_name |
+-------------------------------------------------------------------+
##Example command:
hadoop fs -du /user/hadoop/dir1 \
/user/hadoop/file1 \
hdfs://nn.example.com/user/hadoop/dir1
Exit Code: Returns 0 on success and -1 on error.
source: Apache doc
Prior to 0.20.203, and officially deprecated in 2.6.0:
hadoop fs -dus [directory]
Since 0.20.203 (dead link) 1.0.4 and still compatible through 2.6.0:
hdfs dfs -du [-s] [-h] URI [URI …]
You can also run hadoop fs -help
for more info and specifics.
% of used space on Hadoop cluster
sudo -u hdfs hadoop fs –df
Capacity under specific folder:
sudo -u hdfs hadoop fs -du -h /user
When trying to calculate the total of a particular group of files within a directory the -s
option does not work (in Hadoop 2.7.1). For example:
Directory structure:
some_dir
├abc.txt
├count1.txt
├count2.txt
└def.txt
Assume each file is 1 KB in size. You can summarize the entire directory with:
hdfs dfs -du -s some_dir
4096 some_dir
However, if I want the sum of all files containing "count" the command falls short.
hdfs dfs -du -s some_dir/count*
1024 some_dir/count1.txt
1024 some_dir/count2.txt
To get around this I usually pass the output through awk.
hdfs dfs -du some_dir/count* | awk '{ total+=$1 } END { print total }'
2048
hdfs dfs -count <dir>
info from man page:
-count [-q] [-h] [-v] [-t [<storage type>]] [-u] <path> ... :
Count the number of directories, files and bytes under the paths
that match the specified file pattern. The output columns are:
DIR_COUNT FILE_COUNT CONTENT_SIZE PATHNAME
or, with the -q option:
QUOTA REM_QUOTA SPACE_QUOTA REM_SPACE_QUOTA
DIR_COUNT FILE_COUNT CONTENT_SIZE PATHNAME