Flask url_for URLs in Javascript

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粉色の甜心
粉色の甜心 2021-01-30 10:54

What is the recommended way to create dynamic URLs in Javascript files when using flask? In the jinja2 templates and within the python views url_for is used, what i

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  • 2021-01-30 11:05

    Was searching for a solution, them come up with this solution where

    • No add-on is required

    • No hard-coding URL

    The key is to realise Jinja2 has the ability to render javascript out of the box.


    Setup your template folder to something like below:

    /template
        /html
            /index.html
        /js
            /index.js
    

    In your views.py

    @app.route("/index_js")
    def index_js():
        render_template("/js/index.js")
    

    Now instead of serving the javascript from your static folder. You would use:

    <script src="{{ url_for('index_js') }}"></script>
    

    After all, you are generating the javascript on the fly, it is no longer a static file.


    Now, inside of you javascript file, simply use the url_for as you would in any html file.

    For example using Jquery to make an Ajax request

    $.ajax({
      url: {{ url_for('endpoint_to_resource') }},
      method: "GET",
      success: call_back()
    })
    
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  • 2021-01-30 11:07

    What @dumbmatter's suggesting is pretty much considered a de facto standard way. But I thought there would be a nicer way of doing it. So I managed to develop this plugin: Flask-JSGlue.

    After adding {{ JSGlue.include() }}, you can do the following in your source code:

    <script>
        $.post(Flask.url_for('comment.comment_reply', {article_id: 3}));
    </script>
    

    or:

    <script>
        location.href = Flask.url_for('index', {});
    </script>
    
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  • 2021-01-30 11:09

    In my case, I was trying to dynamically create urls

    I solved my issue as follows (Note: I've swapped out Angular's syntax to {[x]}:

    <ul>
        <li ng-repeat="x in projects">
            {[x.title]}
            {% set url = url_for('static',filename="img/") %}
    
            <img src="{{url}}{[x.img]}">
        </li>
    </ul>
    
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  • 2021-01-30 11:11

    I use this dirty and ugly trick:

    "{{url_for('mypage', name=metadata.name,scale=93,group=2)}}"
    .replace('93/group',scale+'/group')
    

    where scale is the javascript variable I want to use for an AJAX request. So, url_for generate an URL and JavaScript replace the parameter at runtime. The generated code is something like:

    "/ajaxservive/mynam/scale/93/group/2".replace('93/group',scale+'/group')
    

    which is pretty strange, but still can't find more elegant solutions.

    In fact, looking at the code of the linked flask extension, it does the same thing but managing the general case.

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  • 2021-01-30 11:15

    @jeremy's answer is correct and probably the more common approach, but as an alternative answer, note that dantezhu wrote and published a flask extension that claims to do the exact url-route-map-to-javascript translation suggested in the comment.

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  • 2021-01-30 11:18

    The Flask documentation suggests using url_for in your HTML file to set a variable containing the root URL that you can access elsewhere. Then, you would have to manually build the view URLs on top of that, although I guess you could store them similar to the root URL.

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