I have a map where I\'d like to perform a call on every data type object member function. I yet know how to do this on any sequence but, is it possible to do it on an associativ
For fellow programmers who stumble upon this question from google, there is a good way using boost.
Explained here : Is it possible to use boost::foreach with std::map?
Real example for your convenience :
// typedef in include, given here for info :
typedef std::map<std::string, std::string> Wt::WEnvironment::CookieMap
Wt::WEnvironment::CookieMap cookie_map = environment.cookies();
BOOST_FOREACH( const Wt::WEnvironment::CookieMap::value_type &cookie, cookie_map )
{
std::cout << "cookie : " << cookie.first << " = " << cookie.second << endl;
}
enjoy.
Will it work for you ?
class MyClass;
typedef std::pair<int,MyClass> MyPair;
class MyClass
{
private:
void foo() const{};
public:
static void Method(MyPair const& p)
{
//......
p.second.foo();
};
};
// ...
std::map<int, MyClass> Map;
//.....
std::for_each(Map.begin(), Map.end(), (&MyClass::Method));
From what I remembered, C++ map can return you an iterator of keys using map.begin(), you can use that iterator to loop over all the keys until it reach map.end(), and get the corresponding value: C++ map
I wrote this awhile back to do just what you're looking for.
namespace STLHelpers
{
//
// iterator helper type for iterating through the *values* of key/value collections
//
/////////////////////////////////////////////
template<typename _traits>
struct _value_iterator
{
explicit _value_iterator(typename _traits::iterator_type _it)
: it(_it)
{
}
_value_iterator(const _value_iterator &_other)
: it(_other.it)
{
}
friend bool operator==(const _value_iterator &lhs, const _value_iterator &rhs)
{
return lhs.it == rhs.it;
}
friend bool operator!=(const _value_iterator &lhs, const _value_iterator &rhs)
{
return !(lhs == rhs);
}
_value_iterator &operator++()
{
++it;
return *this;
}
_value_iterator operator++(int)
{
_value_iterator t(*this);
++*this;
return t;
}
typename _traits::value_type &operator->()
{
return **this;
}
typename _traits::value_type &operator*()
{
return it->second;
}
typename _traits::iterator_type it;
};
template<typename _tyMap>
struct _map_iterator_traits
{
typedef typename _tyMap::iterator iterator_type;
typedef typename _tyMap::mapped_type value_type;
};
template<typename _tyMap>
struct _const_map_iterator_traits
{
typedef typename _tyMap::const_iterator iterator_type;
typedef const typename _tyMap::mapped_type value_type;
};
}
It's unfortunate that you don't have Boost however if your STL implementation has the extensions then you can compose mem_fun_ref and select2nd to create a single functor suitable for use with for_each. The code would look something like this:
#include <algorithm>
#include <map>
#include <ext/functional> // GNU-specific extension for functor classes missing from standard STL
using namespace __gnu_cxx; // for compose1 and select2nd
class MyClass
{
public:
void Method() const;
};
std::map<int, MyClass> Map;
int main(void)
{
std::for_each(Map.begin(), Map.end(), compose1(std::mem_fun_ref(&MyClass::Method), select2nd<std::map<int, MyClass>::value_type>()));
}
Note that if you don't have access to compose1 (or the unary_compose template) and select2nd, they are fairly easy to write.
C++11 allows you to do:
for (const auto& kv : myMap) {
std::cout << kv.first << " has value " << kv.second << std::endl;
}
C++17 allows you to do:
for (const auto& [key, value] : myMap) {
std::cout << key << " has value " << value << std::endl;
}
using structured binding.
UPDATE:
const auto is safer if you don't want to modify the map.