Understanding nested for loops in javascript

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梦毁少年i
梦毁少年i 2021-01-30 09:39

I\'m learning JavaScript at the moment on freecodecamp and they have an example for nested for loops in one of their excercises:

 var arr = [[1,2], [3,4], [5,6]]         


        
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  • 2021-01-30 10:12
    var arr = [[1,2], [3,4], [5,6]];
    

    This is an array of arrays. It is a little bit easier to read like this:

    var arr = [
                [1,2],
                [3,4],
                [5,6]
              ];
    

    That makes it a little bit easier to see that you have an array of 3 arrays. The outer 'for' will loop through each of 1st level arrays. So the very first outer for loop when i=0 you are going to grab the first inner array [1,2]:

    for (var i=0; i < arr.length; i++) {
        //First time through i=0 so arr[i]=[1,2];
    }
    

    In the inner loop you are going to loop through each of the 3 inner arrays one at a time.

    for (var j=0; j < arr[i].length; j++) {
        //Handle inner array.
    }
    

    This argument grabs the length of the inner array:

    arr[i].length
    

    So on your first time through the outer loop i=0 and arr[i] is going to equal [1,2] because you are grabbing the 0th element. Remember, arrays elements are always counted starting at 0, not 1.

    Finally you are printing out the results with:

    console.log(arr[i][j]);
    

    The first time through you can break it down a little. i=0 and j=0. arr[0][0] which translates as grab the first element from the outer array and then the first element from the first inner array. In this case it is '1':

    [
        [1,2], <-- 0
        [3,4], <-- 1
        [5,6]  <-- 2
    ];
    

    The code will loop through the first first set [1,2], then the second [3,4], and so on.

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  • 2021-01-30 10:13
    function multiplyAll(arr) {
       var product = 1;
       // Only change code below this line
       for (var i = 0; i < arr.length; i++) {
         for (var j = 0; j < arr[i].length; j++) {
           product *= arr[i][j];
           console.log(product)
         }
       }
       // Only change code above this line
       return product;
     }
     // Modify values below to test your code
     multiplyAll([[1], [2], [3]])
     //multiplyAll([[1, 2], [3, 4], [5, 6, 7]]);
     //multiplyAll([[5, 1], [0.2, 4, 0.5], [3, 9]])
    
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  • 2021-01-30 10:14
    1. why the last array in arr[j] is not printed out (where did the [5, 6] go?)

    You may notice that if you print out j as console.log(j), it will print 6 times as 0, 1, 0, 1, 0, 1. And what you're trying to print is arr[j] which [5, 6] will not be displayed because its on arr[2]

    1. why arr[i][j] suddenly eliminates the arrays and just prints out the numbers

    As you state there, arr is an array of 3 arrays. arr[i] represents 3 arrays either of [1, 2], [3, 4] or [5, 6]. And the j in arr[i][j] represents the index of those 3 arrays. This is called Multidimensional Array. arr[i][j] does not eliminate the array, but It selects the value in the index of j inside arr[i].

    1. where the 'undefined' comes from

    It's just chrome thingy when you use console.log. Chrome returns undefined whenever you try to do that. Try to do it on firefox and you will see it no longer.

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  • 2021-01-30 10:19

    The double for loop you have above works like so:

     var arr = [[1,2], [3,4], [5,6]];
    
     for (var i=0; i < arr.length; i++) {
      // i = 0, then we loop below:
      for (var j=0; j < arr[i].length; j++) {
        //here we loop through the array which is in the main array
        //in the first case, i = 0, j = 1, then we loop again, i = 0, j = 1
        console.log(arr[i][j]);
        //after we finish the stuff in the 'j' loop we go back to the 'i' loop 
        //and here i = 1, then we go down again, i, remains at 1, and j = 0, then j = 1
        //....rinse and repeat, 
      }
    }
    

    In plain english:

    We grab the first element in the main array, which is an array itself, we loop through that, and log at each index, this is terminated by our length condition in the second loop. We then move to to the next index of the main array, which is an array itself.... and so on, until we reach the end of the main array

    To access and index in the main array, we need to use array[i] - that index holds an array - so to go INTO that array, we need to use array[i][j]

    Hope that makes sense!

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  • 2021-01-30 10:28

    I know this is an old question... But because this is a popular post from ye olde google search, I feel it's helpful to add a way to visualize what's going on in nested for-loops.

    As a JS teacher, I've found this method super helpful for visually-oriented people and those w/ dyslexia and related things).

    // Original: https://repl.it/@justsml/nested-loop-visualizations
    var nums = [[1,2,3], [4,5,6], [7,8,9]];
    
    console.log('Example w/ Numbers:\n');
    console.log('The array data: ', JSON.stringify(nums));
    
    for (var i=0; i < nums.length; i++) {
      // Main/"top" array - accessing via "arr[i]"
      for (var j=0; j < nums[i].length; j++) {
        // here we loop through the "child" arrays
        let helpfulLabel = `nums[${i}][${j}]`
        let value = nums[i][j]
        console.log(helpfulLabel, 'Value=' + value);
      }
    }
    
    console.log('\nExample w/ String Data:\n');
    var letters = [['a', 'b', 'c'], ['d', 'e', 'f'], ['x', 'y', 'z']];
    console.log('The array data: ', JSON.stringify(letters));
    
    for (var i=0; i < letters.length; i++) {
      for (var j=0; j < letters[i].length; j++) {
        let helpfulLabel = `letters[${i}][${j}]`
        let value = letters[i][j]
        console.log(helpfulLabel, 'Value=' + value);
      }
    }

    Preview of Results

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  • 2021-01-30 10:30
    function multiply(arr) {
        var product = 1;
    
        for (var i = 0; i < arr.length; i++) {
            for (var j = 0; j < arr[i].length; j++) {
                product *= arr[i][j];
            }
        }
    
        return product;
    }
    
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