Get current URL/URI without some of $_GET variables

Question

How, in Yii, to get the current page\'s URL. For example:

http://www.yoursite.com/your_yii_application/?lg=pl&id=15

but excluding the

Answer 1

I don't know about doing it in Yii, but you could just do this, and it should work anywhere (largely lifted from my answer here):

// Get HTTP/HTTPS (the possible values for this vary from server to server)
$myUrl = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] && !in_array(strtolower($_SERVER['HTTPS']),array('off','no'))) ? 'https' : 'http';
// Get domain portion
$myUrl .= '://'.$_SERVER['HTTP_HOST'];
// Get path to script
$myUrl .= $_SERVER['REQUEST_URI'];
// Add path info, if any
if (!empty($_SERVER['PATH_INFO'])) $myUrl .= $_SERVER['PATH_INFO'];

$get = $_GET; // Create a copy of $_GET
unset($get['lg']); // Unset whatever you don't want
if (count($get)) { // Only add a query string if there's anything left
  $myUrl .= '?'.http_build_query($get);
}

echo $myUrl;

Alternatively, you could pass the result of one of the Yii methods into parse_url(), and manipulate the result to re-build what you want.

Answer 2

In Yii2 you can do:

use yii\helpers\Url;
$withoutLg = Url::current(['lg'=>null], true);

More info: https://www.yiiframework.com/doc/api/2.0/yii-helpers-baseurl#current%28%29-detail

Answer 3

For Yii2: This should be safer Yii::$app->request->absoluteUrl rather than Yii::$app->request->url

Answer 4

echo Yii::$app->request->url;

Answer 5

Something like this should work, if run in the controller:

$controller = $this;
$path = '/path/to/app/' 
  . $controller->module->getId() // only necessary if you're using modules
  . '/' . $controller->getId() 
  . '/' . $controller->getAction()->getId()
. '/';

This assumes that you are using 'friendly' URLs in your app config.

Answer 6

Yii 1

Yii::app()->request->url

For Yii2:

Yii::$app->request->url