PagerAdapter start position

Question

I\'m using the following example to impliment my viewPager: http://code.google.com/p/viewpagerexample/issues/list

The problem with this example is that I can\'t figure o

Answer 1

I'm using 3 fragments and on starting my app, the second (middle) fragment will be shown by default. Just I'm using the onResume function and all works great.

@Override
protected void onResume() {
    super.onResume();
    m_viewPager.setCurrentItem(1);
}

Answer 2

Using viewPager.setCurrentItem(newPosition); shows to the user the transition from the starting page to the newPosition, to prevent that from happening and show the newPosition directly as if it was the starting point, I added false to the second parameter something like this:

int newPosition = pages.size()-1; // Get last page position

viewPager.setCurrentItem(newPosition, false); // 2nd parameter (false) stands for "smoothScroll"

Answer 3

I've found a way to set it's position, which is done outside of the class:

 awesomePager = (ViewPager) findViewById(R.id.awesomepager);
 awesomePager.setAdapter(awesomeAdapter);
 awesomePager.setCurrentItem(CurrentPosition);

and it can be limited by calculating the amount of items I want to fit in to it